Answer:
.
Explanation:
Because the track is level and frictionless, the net force on this car-load system will be zero in the horizontal direction. As a result, (by Newton's Second Law of mechanics,) the total momentum of this system in the horizontal direction will stay the same.
Momentum of the car-load system in the horizontal direction, before contact:
- Car:
. - Load: zero (for it is dropped "vertically.")
Combine the two parts to obtain:
.
Because the load stays on the car, the car and the load should have the same horizontal velocity after contact. Let
denote that velocity. Momentum of the system after contact:
- Car:
. - Load:
.
Combine to obtain:
.
Because the total momentum of the system will stay the same:
.
Solve for
to obtain:
.
In other words, the new velocity of the system would be
.
Answer:
50% of unpolarised light passes through the first filter because, on average, 50% of the waves are aligned with the fiter's axis. Intensity is reduced by a factor 0.5.
The second filter then reduces the intensity by a factor cos²(θ)
Explanation:
Answer:
x=2.4t+4.9t^2
Explanation:
This equation is one of the kinematic equations to solve for distance. The original equation is as follows:
X=Xo+Vt+1/2at^2
We know that the ball starts at rest meaning that its initial velocity and position is zero.
X=0+Vt+1/2at^2
Since it is going down the ramp, you can use the acceleration of gravity constant. (9.81 m/s^2) and simplify that with the 1/2.
X=Vt+4.9t^2
Note: Since the positive direction in this problem is down, you are adding the 4.9t^2, but if a question says that the downward direction is negative, you would subtract those values.
Now, substitute in your velocity value.
X=2.4t+4.9t^2
gravity, fluid friction, and i think two more i just cant remember them
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Explanation:
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