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OverLord2011 [107]
3 years ago
15

A violin string E vibrates faster then another violin string G when bowed. Which string produced a sound with higher frequency?​

Physics
1 answer:
Lisa [10]3 years ago
5 0

Violin string E

!!!!!!!!!!!!!!

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Take a car collision as an example, the more you speed up as means of acceleration, the more force will be on impact.
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3 years ago
The potential energy between two atoms in a particular molecule has the form U(x) = 2.1 x 8 − 5.2 x4 where the units of x are le
a_sh-v [17]

Answer:

x\approx 0.948

Explanation:

The correct formula for the potential energy between two atoms in a particular molecule is:

U(x) = \frac{2.1}{x^{8}}-\frac{5.2}{x^{4}}

Where x is the distance.

According to the definitions of potential energy and work, as well as the Work-Energy Theorem and the Principle of Energy Conservation. The relation between that and related force is:

F = -\frac{dU}{dx}

The function is derived in terms of distance:

F (x) = \frac{84}{5\cdot x^{9}} -\frac{104}{5\cdot x^{5}}

Then, it is needed to find at least of x so that F(x) equals to 0.

\frac{84}{5\cdot x^{9}}-\frac{104}{5\cdot x^{5}}=0

\frac{84}{x^{4}}-104 = 0

84-104\cdot x^{4} = 0

x=\sqrt[4]{\frac{84}{104} }

x\approx 0.948

7 0
3 years ago
A rubber rod with a negative 4.0 C (-4.0 x 10-6 C) charge is 10 cm east of a pith ball with a positive charge of 5.0 C. A plas
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552. cm eastthat's the answer
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3 years ago
Was the first chemist to organize elements by atomic number
Arturiano [62]

Answer:

Dimitri Mendeleev

Explanation:

This man started the development of the periodic table, by arranging elements by atomic mass.  

5 0
3 years ago
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If two charged objects in a laboratory are brought to a distance of 0.22 meters away from each other. What is
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Answer:

q_2=2.47\times 10^{-4}\ C

Explanation:

The charge on one object, q_1=9.9\times 10^{-5}\ C

The distance between the charges, r = 0.22 m

The force between the charges, F = 4,550 N

Let q₂ is the charge on the other sphere. The electrostatic force between two charges is given by the formula as follows :

F=\dfrac{kq_1q_2}{r^2}\\\\q_2=\dfrac{Fr^2}{kq_1}\\\\q_2=\dfrac{4550\times (0.22) ^2}{9\times 10^9\times 9.9\times 10^{-5}}\\\\q_2=2.47\times 10^{-4}\ C

So, the charge on the other sphere is 2.47\times 10^{-4}\ C.

7 0
3 years ago
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