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Vaselesa [24]
3 years ago
15

Two spherical objects have masses of 200 kg and 500 kg. Their centers are separated by a distance of 25 m. Find the gravitationa

l attraction between them.
Physics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

1.07 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1 = 200kg

Mass 2  = 500kg

Distance of separation  = 25m

Unknown:

Gravitational attraction between the two bodies  = ?

Solution:

To solve this problem, we use the equation of the universal gravitation;

                 F  = \frac{G mass 1  x mass 2}{r^{2} }  

G is the universal gravitation constant  = 6.67 x 10⁻¹¹Nm²kg⁻²

r is the distance

 Now insert the parameters and solve;

    F  = \frac{6.67 x 10^{-11} x 200 x 500 }{25^{2} }   = 1.07 x 10⁻⁸N

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que tiempo tarda juan en su carro al llegar al trabajo si lleva una velocidad de 25 m/s a una distancia de 5m
kramer

Answer:

0.2s

Explanation:

Given parameters:

Speed  = 25m/s

Distance  = 5m

Unknown:

Time taken for Juan to get to his work  = ?

Solution:

To solve this problem we use the relationship below:

 

   Speed  = \frac{distance}{time}  

  Time  =  \frac{distance }{speed}  

So;

   Time  = \frac{5}{25}   = 0.2s

4 0
3 years ago
Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 48.
galina1969 [7]

Given:

The force of attraction is F = 48.1 N

The separation between the charges is

\begin{gathered} r=\text{ 60.9 cm} \\ =\text{ 60.9}\times10^{-2}\text{ m} \end{gathered}

Also, the magnitude of charge q1 = q2 = q.

To find the magnitude of charge.

Explanation:

The magnitude of charge can be calculated by the formula

\begin{gathered} F=\frac{k(2q)}{r^2} \\ q=\frac{Fr^2}{2k} \end{gathered}

Here, k is the Coulomb's constant whose value is

k\text{ = 9}\times10^9\text{ N m}^2\text{ /C}^2

On substituting the values, the magnitude of charge will be

\begin{gathered} q=\frac{48.1\times(60.9^\times10^{-2})^2}{2\times9\times10^{^9}} \\ =9.91\times10^{-10}\text{ C} \\ =9.91\times10^{-4}\text{ }\mu C \end{gathered}

Thus, the magnitude of each charge is 9.91 x 10^(-4) micro Coulombs.

6 0
2 years ago
Two vectors A and B have components (0,1) and (-1,3) respectivly. What is the magnitude of the sum of these two vectors
Ymorist [56]
A = <0,1>
B = <-1,3>
then
A + B = < 0+-1 , 1+3 > = <-1, 4>
magnitude = sqrt( (-1)^2 + (4)^2 )
= sqrt( 1 + 16)
= sqrt(17)
3 0
3 years ago
7. A 25 N block is lowered 1.2 m by a 20 N force.
Sauron [17]

Answer:

this answer your question

3 0
3 years ago
Classify Cd2+ Mn2+ Kr Zr as Paramagnetic or diamagnetic
jeka57 [31]
We classify the elements as follows:

<span>Cd2+ = Diamagnetic
Mn2+ = Paramagnetic
Kr = Diamagnetic
Zr = Paramagnetic

Diamagnetic when </span><span>all electrons are paired which means that in an orbital an electron spins clockwise and another spins anticlockwise while paramagnetic is the opposite.</span><span>


</span>
5 0
3 years ago
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