All categories

3 years ago

How many kilojoules of heat are released when 0.72 mole of oxygen gas are used to combust methane?

Chemistry

1 answer:

KonstantinChe [14]3 years ago

6 0

0.72 mole of oxygen would produce 320.4 kJ of heat.

Explanation:

CH₄ (g) + 2O₂ (g) → CO₂ (g) + 2H₂O (ℓ) + 890kJ

According to the equation,

2 moles of O₂ produces 890 kJ of heat

So, 0.72 moles of O₂ will produce:

$= \frac{890}{2} X 0.72\\\\= 445 X 0.72\\\\= 320.4 kJ$

Therefore, 0.72 mole of oxygen would produce 320.4 kJ of heat.

You might be interested in

Urea makes up a significant amount of urine, and is the chemical that the body uses to rid cells of unwanted carbon dioxide and

Ira Lisetskai [31]

Urea is highly soluble in water. When it is allowed to dissolve in water in the presence of heat, it will yield ammonia and carbon dioxide. The reaction is shown below:

NH2-CO-NH2 + H2O ⇒ 2 NH3 + CO2

As you can observe in the stoichiometric equations, 1 molecule of water can dissolve with 1 mole of urea.

3 0

3 years ago

8 Fe + Sg → 8 Fes How many grams of FeS is produced from 0.3 mol Sg?

frozen [14]

Answer:

Explanation:

Molar ratio for Sg : FeS = 1:8

If there are 0.3 moles for Sg

Therefore, 0.3 × 8 =2.4 moles of FeS

Mass = Moles/ Mr

Mr of FeS = 56+32=88

So mass = 2.4/88

Mass= 0.027g

6 0

2 years ago

Blood ph is kept near a value of 7.3 - 7.5 because of

Ede4ka [16]

Answer: Neutral Value

Explanation: pH of the blood is maintained at 7.0 to 7.5that is neutral value.

This is because if the pH of the is lower than the maintained value then it will become acidic .

Acidic pH can cause the medical urgency known as acidosis leading to vomiting, diarrhea etc.

If the pH becomes higher, then the blood will become basic in nature and it can also leas to the death of the person.

That is why the pH of the blood is maintianed at neutral value of 7.0 to 7.5

5 0

3 years ago

Read 2 more answers

How do ionic bonds differ from covalent bonds?

Alja [10]

Ionic bonds are a metal and a non metal bond and a covalent bond is two no metals banded together.

4 0

2 years ago

Given the following data: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39

nalin [4]

Answer:

ΔH° = -11 kj

Explanation:

Step 1: Data given

1) Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ

2) 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39 kJ

3) Fe3O4(s) + CO(g) → 3 FeO(s) + CO2(g) ΔH = +18 kJ

Step 2: The balanced equation

FeO + CO → Fe + CO2

Step 3: Calculate ΔH for the reaction FeO(s) + CO(g) → Fe(s) + CO2(g).

To get this equation, we need to combine the 3 equations

We have to multiply the third equation by 2.

2Fe3O4(s) + 2CO(g) → 6 FeO(s) + 2CO2(g) ΔH = +54 kJ

This equation we add to the second equation

3Fe2O3(s) + CO(g) + 2Fe3O4(s) + 2CO(g) → 2Fe3O4(s) + CO2(g) + 6FeO(s) + 2CO2 (g)

3Fe2O3(s) + 3CO(g) → 3CO2(g) + 6FeO(s)

ΔH° = 2*18 + (-39) = 36 - 39 = -3 kJ

This new equation we will divide by 3

3Fe2O3(s) + 3CO(g) → 3CO2(g) + 6FeO(s)

Fe2O3(s) + CO(g) → CO2(g) + 2FeO(s)

ΔH° =-3/3 = -1 kJ

Now we will substract this new equation from the first equation

Fe2O3(s) + 3CO(g) - Fe2O3(s) - CO(g) → 2Fe(s) + 3CO2(g) -2FeO(s) - CO2(g)

2CO(g) + 2FeO(s) → 2Fe(s) + 2CO2(g)

ΔH° = -23kJ +1kJ

ΔH° = -22 kj

The next equation we will divide by 2

2CO(g) + 2FeO(s) → 2Fe(s) + 2CO2(g)

CO(g) + FeO(s) → Fe(s) + CO2(g)

ΔH° = -22kJ /2

ΔH° = -11 kj

7 0

3 years ago