When the serving team makes a mistake giving the other team a point and<br> the serve

Which structure is larger cell, organ , multicellular or cell structure

hoa [83]

Answer:

organ is larger cell..............

7 0

3 years ago

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Acceleration is best defined as the rate of change of __________ of an object. A. position B. force C. speed D. velocity 2. Whic

Fittoniya [83]

Velocity!
Hope this helps!

7 0

3 years ago

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When switched on, the grinding machine accelerates from rest to its operating speed of 3550 rev/min in 10 seconds. When switched

Paraphin [41]

Answer:

During start total turns

$N_1 = 296 turn$

After half of the time total turns

$N_3 = \frac{29.6 + 0}{2}(5) = 74 turns$

Total number of turns during it stop

$N_2 = \frac{59.17 + 0}{2}(31) = 917 turn$

After half of the time total turns

$N_4 = 688 turns$

Explanation:

Initially the machine is at rest and then starts rotating with speed 3550 rev/min

now we will have

$f = \frac{3550}{60} = 59.17 rev/s$

now we know that it took 10 s to reach the speed

so angular acceleration is given as

$\alpha = \frac{\omega_f - \omega_i}{t}$

$\alpha = \frac{59.17- 0}{10} = 5.917 rev/s^2$

now it stops in 31 s so the angular deceleration is given as

$\alpha_2 = -\frac{59.17}{31} = -1.91 rev/s^2$

now initially number of turn to reach the given speed

$N_1 = \frac{59.17 + 0}{2}(10) = 296 turn$

number of turns during it stop

$N_2 = \frac{59.17 + 0}{2}(31) = 917 turn$

Now during startup speed after t = 5 s is given as

$\omega_1 = (5.917)(5) = 29.6 rev/s$

$N_3 = \frac{29.6 + 0}{2}(5) = 74 turns$

now during it stop the speed after half the time is given as

$\omega_2 = 59.17 - (1.91)(15.5) = 29.56 rev/s$

now the number of turns is given as

$N_4 = \frac{59.17 + 29.56}{2}(15.5)$

$N_4 = 688 turns$

5 0

3 years ago

The purpose of a fuse or circuit breaker is _____.

ExtremeBDS [4]

What a sloppy question ! The purpose of a fuse or circuit breaker is to shut down the circuit when current reaches a magnitude indicating danger due to a serious malfunction. When current IS flowing in the circuit, it's always flowing at the same speed.

3 0

3 years ago

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QUESTION 1 If you do 1,000 J of work on a system and remove 500 J of heat from it, what is the change in its internal energy?

Mazyrski [523]

1. U = Q + W
U = -500 + 1000
U = 500 J

2. The first law of thermodynamic is about the law of conservation of energy where energy in should be equal to energy out.

3. It is the windmill that does not transform energy from heat to mechanical instead it is the transforms the opposite.

4. In a heat engine, work is used to transfer thermal energy from a hot reservoir to a cold one.

5. 5.00 × 10^4 J - 2.00 × 10^4 J = 3.00 × 10^4 J

6. To increase the work done, we raise the temperature of the cold reservoir.

7 0

3 years ago

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When the serving team makes a mistake giving the other team a point and the serve