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BARSIC [14]
3 years ago
14

Sometimes called the "River of Grass," _________ Is a vast wetland

Chemistry
2 answers:
timama [110]3 years ago
6 0

Answer: A

Explanation:

i just know

Andreyy893 years ago
6 0
A is the answer to this question
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Pls help--How do double-pane windows affect the transfer of heat between the inside and outside air?
Margarita [4]

Answer:C

Explanation:

6 0
3 years ago
How many miles of a gas at 100 c does it take to fill a 1.00 l flask to a pressure of 152kPa
Hatshy [7]

The complete question is as follows: How many moles of a gas at 100 c does it take to fill a 1.00 l flask to a pressure of 152kPa

Answer: There are 0.0489 moles of a gas at 100^{o}C is required to fill a 1.00 l flask to a pressure of 152kPa.

Explanation:

Given: Volume = 1.00 L,    

Pressure = 152 kPa (1 kPa = 1000 Pa) = 152000 Pa

Convert Pa into atm as follows.

1 Pa = 9.86 \times 10^{-6} atm\\152000 Pa = 152000 \times \frac{9.86 \times 10^{-6}atm}{1 Pa}\\= 1.5 atm

Temperature = 100^{o}C = (100 + 273) K = 373 K

Using the ideal gas formula as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.5 atm \times 1.0 L = n \times 0.0821 L atm/mol K \times 373 K\\n = \frac{1.5 atm \times 1.0 L}{0.0821 L atm/mol K \times 373 K}\\n = 0.0489 mol

Thus, we can conclude that there are 0.0489 moles of a gas at 100^{o}C is required to fill a 1.00 l flask to a pressure of 152kPa.

5 0
3 years ago
What is h2o? I’m in 1st grade
Crazy boy [7]

Answer:

Water

Explanation:

H20 means

H = Hydrogen

2 = 2 Hydrogen atoms

O = Oxygen (1 atom)

Thanks!

Mark me brainliest!

5 0
3 years ago
Read 2 more answers
Consider a gray and opaque surface at 0°c in an environment at 25°C. The surface has an emissivity of 0.8. if the radiation in
valina [46]

The radiosity of this surface is 299.95W/m².

<h3>Calculation :</h3>

Given, € 0.8

Ta=0°C 273K

For opaque body., T = 0

a+ p = 1

€ = a (Kirchoff's Law)

p = (1-E)

Radiosity = leaving energy from the surface

= px 240 +€σT4

= (1-E) × 240 +0.8 x 5.67 x 10-8 (2734)

= (1-0.8) × 240 +0.8 x 5.67 × 10-8 (2734)

= 299.95W/m²

So, now after doing the calculations we can say that the radiosity of the surface was 299.95W/m².

To know more about Radiosity please click here : brainly.com/question/14937321

#SPJ4

7 0
2 years ago
What can an experiment to use to distinguish between a strong acid and a strong base
aivan3 [116]

The pH meter can only be used to differentiate between weak and strong acids providing that the concentrations are known. However, it is convenient to determine the concentration of an acid (or base) by titration.

4 0
4 years ago
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