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solmaris [256]
3 years ago
7

Standard 6 multiple choice questions English paper​

Chemistry
2 answers:
Charra [1.4K]3 years ago
5 0
So what’s the question? I’m confused
nikdorinn [45]3 years ago
5 0

Answer:

please attach the images in the attachment and then I 'll b able to answer your questions regarding any subject!!

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How to get the formulas for these compounds
Travka [436]
So what you’re going to do is basically the + and - in each top hand corner is the charge of compound, so for example Li has a charge of +1 while Br has a charge of -1 , to write the formula you need to get the charges to cancel out ( equal zero) so luckily this was easy because -1 +1 =0 ! So it would be LiBr. Though for another example Al has a charge of 3+ while br has a charge of -1 and these do not equal zero, so as a result you have to add more br making the Formula AlBr3! Hope this helps!
5 0
3 years ago
Need Help ASAP
bagirrra123 [75]

a. pH=2.07

b. pH=3

c. pH=8

<h3>Further explanation</h3>

pH=-log [H⁺]

a) 0.1 M HF Ka = 7.2 x 10⁻⁴

HF= weak acid

\tt [H^+]=\sqrt{Ka.M}\\\\(H^+]=\sqrt{7.2.10^{-4}\times 0.1}\\\\(H^+]=8.5\times 10^{-3}\\\\pH=3-log~8.5=2.07

b) 1 x 10⁻³ M HNO₃

HNO₃ = strong acid

\tt pH=-log[1\times 10^{-3}]=3

c) 1 x 10⁻⁸ M HCl

\tt pH=-log[1\times 10^{-8}]=8

5 0
3 years ago
What is formed when two or more elements are bonded together?​
Nadusha1986 [10]

Answer:

a compound

Explanation:

a compound consists of two or more elements combined

6 0
3 years ago
Read 2 more answers
Enter the appropriate symbol for an isotope of calcium-42 corresponding to the isotope notation AZX
Sergio [31]
<span>40 20Ca this is the appropriate symbol for an isotope of calcium-42 corresponding to the isotope notation AZX</span><span />
3 0
3 years ago
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12.A piece of magnesium is in the shape of a cylinder with a height of 5.62 cm
yaroslaw [1]

Answer:

Density, d = 1.779 g/cm³

Explanation:

The density of a material is given by its mass per unit volume.

Here, height of a piece of magnesium cylinder, h = 5.62 cm

Its diameter, d = 1.34 cm

Radius = 0.67 cm

Volume of he cylinder,

V=\pi r^2 h\\\\\text{Putting the value of r and h, we get :}\\\\V=(\pi \times (0.67)^2\times 5.62)\ cm^3

d=\dfrac{m}{V}\\\\d=\dfrac{14.1\ g}{(\pi \times (0.67)^2\times 5.62)\ cm^3}\\\\d=1.779\ g/cm^3

So, the density of the sample is 1.779 g/cm³.

4 0
3 years ago
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