Answer:
1088.9N/m2
Explanation:
Calculation for What pressure is exerted
First step is to find the area of bottom of the tank using formula
Area=Width*breadth
Let plug in the formula
Area=0.5*0.9
Area=0.45m2
Now let calculate what pressure is exerted using this formula
Pressure=Force/Area
Where,
Force=Mass *Gasoline
Area=Width of the tank* Length of the tank
Let plug in the formula
Pressure=50*9.8/0.5*0.9
Pressure=490/0.45
Pressure=1088.9N/m2
Therefore What pressure is exerted is 1088.9N/m2
The initial velocity of go-kart is 2.5 m/s.
<u>Explanation:</u>
Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.
In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.
As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.

Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,

Initial velocity = 0.5 × 5 = 2.5 m/s.
So the initial velocity of go-kart is 2.5 m/s.
Answer:
The period of rotation is
T=8.025s
Explanation:
The person is undergoing simple harmonic motion on the wheel
Given data
mass of the person =75kg
Radius of wheel r=16m
Velocity =8.25m/s
The oscillating period of simple harmonic motion is given as
T=(2*pi)/2=2*pi √r/g
Assuming that g=9.81m/s
Substituting our data into the expression we have
T=2*3.142 √ 16/9.81
T=6.284*1.277
T=8.025s
Answer:
6.32s
Explanation:
Given parameters:
Length of track and distance covered = 200m
Acceleration = 10m/s²
Unknown:
Time taken to cover the track = ?
Solution:
To solve this problem, we apply one of the motion equations as shown below:
S = ut +
at²
S is the distance covered
t is the time taken
a the acceleration
u is the initial velocity
The initial velocity of Superman is 0;
So;
S =
at²
200 =
x 10 x t²
200 = 5t²
t² = 40
t = 6.32s
A. True. You can use displacement to determine the volume of solids and liquids.