4% of 110 is 4.4. So the possible range of speeds is the interval from 110-4.4 till 110+4.4.
105.6 till 114.4
For any mass m:
a = F/m
v = √2*F/m*s = √2F/sm = k/√m
Momentum = mv = k√m
Energy = 1/ mv² = 1/2 m.k²/m = 1/2k²
SO
Both will have same energy
The larger mass will have greater momentum
Answer:
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Answer:
f_D = =3.24 N/m
Explanation:
data given
properties of air
k = 0.0288 W/m.K
WE KNOW THAT
Reynold's number is given as
= 1.941 *10^4
drag coffecient is given as
solving for f_D
Drag coffecient for smooth circular cylinder is 1.1
therefore Drag force is
f_D = =3.24 N/m
West to east.
The earth is spinning on its own axis. Thus, the area of the equator directly hit by the sun's heat and more solar radiation compared to any other area. That same heat warmth the atmosphere. Warm air rises towards the pole which is cooler. This is the reason of constant movement of the atmosphere.
The Coriolis force governed the air flows towards the pole. While the earth is spinning plus the movement of air north or south, the air follows a <span>curved path, toward the east.</span>
