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Bumek [7]
3 years ago
14

Describe three objects in your house that use LEDs ​

Engineering
2 answers:
Firlakuza [10]3 years ago
5 0

Answer:

1. Accent Lighting: Often used on stair wells and kitchen islands, LED accent lighting is a cost-effective way to light your home at night – and avoid stubbing your toe in the middle of the night. It’s also effortless to recreate using flexible LED strips or rope lights, which can fit almost anywhere.

2. Faucets & Showerheads: Adding LEDs to a bathroom or kitchen faucet, or a showerhead, produces a neat, futuristic effect especially when paired with streamlined chrome. All you’ll need to do is install a new showerhead to enjoy a shower in bright blue or purple hues. There’s even a designer line of LED sinks and tubs if you care to extend the look to the rest of your bathroom.

3. Wallpapers: LED walls are nothing new; folks have been rigging those up through various methods for years, but now there is LED wallpaper – in a few different styles from high-tech geekery, to more subtle designs. If that’s far too much effort, you can still take part in the trend with the LED wave projector, which drapes your wall in cool blue tones. There are also some lovely ceiling designs that use fibre optics that would probably be quite easy to duplicate with LEDs as well.

4. Centerpieces: Much like adding a tiny, cool plastic LED light disk into a faux candle provides you with a warm flame effect, putting colored LED disks into centerpieces will add atmosphere to the party. Likewise, waterproof LEDs can be added to glasses, and strands of LEDs can be worked into flower arraignments.

5. Planter Pots: Green thumbs don’t get left out when it comes to LEDs – far from it. In fact, LEDs are commonly used to help plants grow. So, an LED planter pot is another perfect combination of style and substance. Studio Shulab’s Lightpot and Rotoluxe both have excellent examples; Firebox has a solar powered version.

Hope it helps

Please mark me as the brainliest

Thank you

Mashutka [201]3 years ago
4 0
Light fixtures lamps and tv i think
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A rigid, sealed tank initially contains 2000 kg of water at 30 °C and atmospheric pressure. Determine: a) the volume of the tank
Bad White [126]

Given:

mass of water, m = 2000 kg

temperature, T = 30^{\circ}C = 303 K

extacted mass of water = 100 kg

Atmospheric pressure, P = 101.325 kPa

Solution:

a) Using Ideal gas equation:

PV = m\bar{R}T                                        (1)

where,

V = volume

m = mass of water

P = atmospheric pressure

\bar{R} = \frac{R}{M}

R= Rydberg's constant = 8.314 KJ/K

M = molar mass of water = 18 g/ mol

Now, using eqn (1):

V = \frac{m\bar{R}T}{P}

V = \frac{2000\times \frac{8.314}{18}\times 303}{101.325}

V = 2762.44 m^{3}

Therefore, the volume of the tank is V = 2762.44 m^{3}

b) After extracting 100 kg of water, amount of water left, m' = m - 100

m' = 2000 - 100 = 1900 kg

The remaining water reaches thermal equilibrium with surrounding temperature at T' = 30^{\circ}C = 303 K

At equilibrium, volume remain same

So,

P'V = m'\bar{R}T'

P' = \frac{1900\times \frac{8.314}{18}\times 303}{2762.44}      

Therefore, the final pressure is P' = 96.258 kPa

4 0
3 years ago
In terms of the atomic radius, R, determine the distance between the centers of adjacent atoms for the FCC crystal structure alo
timama [110]

Answer:

The distance between the centers of adjacent atoms for the FCC crystal structure along the [100] is 2R√2

Explanation:

From the image uploaded, a Face centered cubic structure (100) plane, there is one atom at each of the four cube corners, each of which is shared with four adjacent unit cells, while the center atom lies entirely within the unit cell.

In terms of the atomic radius, R, we determine the distance between the centers of adjacent atoms.

Let this distance = AC

the two adjacent sides = AB and BC

AB = a = 2R

BC = a = 2R

Using Pythagoras theorem

AC² = AB² + BC²

AC² = a² + a²

AC² = 2a²

AC = √2a²

AC = a√2

But a = 2R

AC = 2R√2

Therefore,  the distance between the centers of adjacent atoms for the FCC crystal structure along the [100] is 2R√2

6 0
3 years ago
Technician a says that if a tapered roller bearing is adjusted to loose
Effectus [21]
The technician is true
5 0
3 years ago
Give two causes that can result in surface cracking on extruded products.
Andreas93 [3]

Answer:

1. High friction

2. High extrusion temperature

Explanation:

Surface cracking on extruded products are defects or breakage on the surface of the extruded parts. Such cracks are inter granular.

           Surface cracking defects arises from very high work piece temperature that develops cracks on the surface of the work piece. Surface cracking appears when the extrusion speed is very high, that results in high strain rates and generates heat.

          Other factors include very high friction that contributes to surface cracking an d chilling of the surface of high temperature billets.

6 0
3 years ago
How are project deliverables determined?
Greeley [361]

Answer:

The essence including its problem is listed throughout the clarification section following.

Explanation:

Projects build deliverable that seem to be the products of the venture or indeed the implementation of the project. This ensures that perhaps the agile methodology may be as broad as either the goal of the study itself as well as the coverage that would be part of a much larger venture.

For every other production to have been marked as "deliverable" within the same project, this should satisfy a few eligibility requirements:

  • It should be within the development of the work.
  • The interested parties-external or internal-must consent to the above. This is perhaps the product of hard effort.

So that the above seems to be the right answer.

7 0
3 years ago
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