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Westkost [7]
3 years ago
6

FB and were to bond the difference in electronegativity would be

Chemistry
1 answer:
Kay [80]3 years ago
3 0
Poler covalent
again don’t quote me on it i’m just trying my best with what i remember
You might be interested in
the pressure in a car tire is 198 kpa at 27°C. After a long drive the pressure is 225 kpa. what is the temperature of the air in
Grace [21]

Answer:

340.9°k ~ 67.8°C

Explanation:

This is an example of Gay-Lussac's law, which states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature. This means that if the volume increases, so does the temperature, and vice versa.

The equation for this gas law is:

P1/T1 = P2/T2

Known

P1 = 198 kPa

T1 = 27°C + 273.15 = 300°K ← Temp. must be in Kelvins

P2 = 225 kPa

T2 = ?

Solution

Rearrange the equation to isolate T2

Input the known values and solve.

T2 = T1P2/P1

Where:

T2 = 300°K × 225kPa/198kPa = 340.91°K

T2 in °C = 340.91°K − 273.15 = 67.8°C

note: answers were rounded off to one decimal point.

7 0
3 years ago
What is the formula for the compound?
4vir4ik [10]

Answer:

the correct answer is CO2 (the last one)

7 0
3 years ago
Read 2 more answers
Someone please help?!?
ss7ja [257]

Answer: to late sorry maybe next time

Explanation:

4 0
3 years ago
What mass of hydrochloric acid (in grams) can 2.7 g of sodium bicarbonate neutralize? (Hint: Begin by writing a balanced equatio
Julli [10]

Answer:

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

Explanation:

Step 1: Data given

Mass of sodium bicarbonate = 2.7 grams

Step 2: The balanced equation

HCl + NaHCO3 ⇔  NaCl + H2O + CO2

Step 3: Calculate moles NaHCO3

moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles

Step 4: Calculate moles HCl

For 1 mol NaHCO3 we need 1 mol HCl

For 0.032 moles NaHCO3 = 0.032 moles HCl

Step 5: Calculate mass HCl

Mass HCl = moles HCl * molar mass HCl

mass HCl = 0.032 * 36.46 g/mol= 1.17 grams

1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate

3 0
3 years ago
how many moles of sodium are needed to react with sulfuric acid to produce 3.75 moles of sodium sulfate according to the followi
anastassius [24]
Hello!
<span>
You'll need to react 7,5 moles of Sodium with sulfuric acid to produce 3.75 moles of sodium sulfate
</span>
First of all, you need to balance the reaction. The balanced reaction is shown below (ensuring that the Law of Conservation of Mass is met on both sides):

2Na + H₂SO₄ → Na₂SO₄ + H₂

Now, all that you have to do is to use molar equivalences in this reaction applying the coefficients to calculate the moles of Sodium that you'll need:

molesNa=3,75moles Na_{2} SO_4* \frac{2 moles Na}{1 mol Na_{2} SO_4} =7,5 moles Na 

Have a nice day!
5 0
3 years ago
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