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alexandr402 [8]
3 years ago
12

Which describes how radiation moves?

Chemistry
2 answers:
goldenfox [79]3 years ago
8 0

Answer: B

Explanation:LATE IM LATE BUT ITS

vazorg [7]3 years ago
4 0
Hey <span>wademcelroy2005, thanks for submitting your question to Brainly!

The answer to your question is </span><span>B:Radiation moves from a warmer object to a cooler object</span>
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When an atom of calcium (Ca) forms an ion by losing two electrons, what is the ion’s type and charge?
posledela

Answer:

cation +2

Explanation:

A cation is a positively charged ion, while an anion is a negatively charged ion. Contrary to how it sounds, when an atom loses electrons, it's charge becomes more positive. Since the calcium atom lost 2 electrons, it is a positive (+2) ion.

5 0
3 years ago
Read 2 more answers
Ground water, the largest source of fresh water, is stored in bodies of rock and or sediment
zepelin [54]
D. Aquifers
Hope this helps chief.
7 0
3 years ago
6. A sample of a gas has a mass of 0.527 g. Its volume is 0.35 L at a temperature of 88 degree Celsius and a pressure of 945 mm
Stels [109]

<u>Answer:</u> The molar mass of the gas is 35.87 g/mol.

<u>Explanation:</u>

To calculate the mass of gas, we use the equation given by ideal gas:

PV = nRT

or,

PV=\frac{m}{M}RT

where,

P = Pressure of gas = 945 mmHg

V = Volume of the gas = 0.35 L

m = Mass of gas = 0.527 g

M = Molar mass of gas = ? g/mo

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of gas =  88^oC=[88+273]=361K

Putting values in above equation, we get:

945mmHg\times 0.35L=\frac{0.527g}{M}\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 361K\\\\M=35.87g/mol

Hence, the molar mass of the gas is 35.87 g/mol.

5 0
4 years ago
A voltaic cell is made using a lead electrode and copper electrode. The electrolytes for each half cell are lead nitrate and cop
lisov135 [29]

The cell notation is Pb_{(s)}  Pb^{2+} _{(aq)} ║Cu^{+2}_{aq}  Cu_{(s)} and the cell potential is 0.464

The reaction occurred while losing of hydron is known as oxidation reaction

We can also tell that the reaction occurred while gaining of oxygen atom is known as oxidation reaction.

The reaction occurred while gaining of hydrogen is known as reduction reaction or we can say that the reaction occurred while losing oxygen atom is known as reduction reaction

An electrochemical cell's cell potential is defined as the difference in potential between two half cells. The electrons' capacity to go from one half cell to the other is what causes the potential difference. As a result of the chemical reaction being a redox reaction, electrons can travel across electrodes.

Calculating the Cell potential

E°cell  = E°(reduction) - E°(oxidation)

           = 0.34 - (-0.0124)

           = 0.464

Hence the cell potential is 0.464

Learn more about Cell potential here

brainly.com/question/11638563

#SPJ10

6 0
2 years ago
What is the pH of a 1.0 L buffer made with 0.300 mol of HF (Ka = 6.8 × 10⁻⁴) and 0.200 mol of NaF to which 0.150 mol of HCl were
irinina [24]

Answer:

pH = 2.21

Explanation:

Hello there!

In this case, according to the reaction between NaF and HCl as the latter is added to the buffer:

NaF+HCl\rightarrow NaCl+HF

It is possible for us to see how more HF is formed as HCl is added and therefore, the capacity of this HF/NaF-buffer is diminished as it turns acid. Therefore, it turns out feasible for us to calculate the consumed moles of NaF and the produced moles of HF due to the change in moles induced by HCl:

n_{HF}^{new}=0.300mol+0.150mol=0.450mol\\\\n_{NaF}^{new}=0.200mol-0.150mol=0.050mol

Next, we calculate the resulting concentrations to further apply the Henderson-Hasselbach equation:

[HF]=\frac{0.450mol}{1.0L} =0.450M

[NaF]=\frac{0.050mol}{1.0L} =0.050M

Now, calculated the pKa of HF:

pKa=-log(6.8x10^{-4})=3.17

We can proceed to the HH equation:

pH=pKa+log(\frac{[NaF]}{[HF]} )\\\\pH=3.17+log(\frac{0.05M}{0.45M} )\\\\pH=2.21

Best regards!

6 0
3 years ago
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