Answer:
the percentage of carpet is calcium carbonates is 12.456734190
The mass and Volume is different even thought they have a similar shape and size
Respuesta:
90.0 %
Explicación:
Paso 1: Escribir la ecuación química balanceada
N₂ + 3 H₂ ⇒ 2 NH₃
Paso 2: Calcular el rendimiento teórico de NH₃ a partir de 140 g de N₂
En la ecuación balanceada, participan de N₂: 1 mol × 28.01 g/mol = 28.01 g y de NH₃: 2 mol × 17.03 g/mol = 34.06 g.
140 g N₂ × 34.06 g NH₃ /28.01 g N₂ = 170 g NH₃
Paso 3: Calcular el rendimiento porcentual de NH₃
El rendimiento experimental de NH₃ es 153 g. Podemos calcular el rendimiento porcentual usando la siguiente fórmula.
R% = rendimiento experimental / rendimiento teórico × 100%
R% = 153 g / 170 g × 100% = 90.0 %
Answer:
3.1 moles of ammonia
18.67× 10²³ molecules
Mass = 52.7 g
Explanation:
Given data:
Number of atoms of hydrogen = 5.68×10²⁴ atoms
A) Number of molecules of ammonia = ?
Solution:
First of all we will calculate the number of moles of hydrogen.
1 mole = 6.022× 10²³ atoms
5.68×10²⁴ atoms × 1 mol / 6.022× 10²³ atoms
0.94×10¹ mol
9.4 moles of hydrogen
Moles of ammonia:
3 moles of hydrogen are present in one mole of ammonia.
9.4 moles of hydrogen = 1/3×9.4 =
3.1 moles of ammonia
Number of molecules of ammonia:
1 mole contain 6.022× 10²³ molecules.
3.1 mol × 6.022× 10²³ molecules / 1 mol
18.67× 10²³ molecules
c) Mass of sample = ?
Mass = number of moles × molar mass
Mass = 3.1 moles × 17 g/mol
Mass = 52.7 g
