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crimeas [40]
2 years ago
9

HELP AN ILL PUT U IN BRAINLIEST - THANKYOU

Chemistry
2 answers:
Triss [41]2 years ago
5 0

Answer:

it is D

Explanation:

asambeis [7]2 years ago
3 0

Answer:

D

Explanation:

The amount increased to a certain point then decreased

You might be interested in
How much heat is required to melt 26.0 g of ice at its melting point?
MAXImum [283]

Answer:

Heat required to melt 26.0 g of ice at its melting point is 8.66 kJ.

Explanation:

Number of moles of water in 26 g of water: 26× \frac{1}{18.02} moles

                                                                      =1.44 moles

The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol.

we have relation as:

                                           q = n × ΔH

where:

q  = heat

n  = moles

Δ H  = enthalpy

So calculating we get,

                                        q= 1.44*6.02 kJ

                                        q= 8.66 kJ

We require 8.66 kJ of energy to melt 26g of ice.

                       

8 0
3 years ago
PLEASE HELP- CHEMISTRY QUIZ
jonny [76]

Answer:

•Li2S is at a low melting point

•NCL3 is a covalent bond

Explanation:

Just some notes to help you:))

Covalent Bonds: A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons

5 0
3 years ago
Can synthetic chemicals have origins in nature, or are they completely man-made? Give examples and
Aneli [31]
Yes they can have origins in nature. A bunch of the elements on the periodic table are chemicals and this are basic substances and cannot be man made.
6 0
3 years ago
Where would you look for igneous rocks? Why?
Brut [27]

Answer:

Where Igneous Rocks Are Found. The deep seafloor (aka... the oceanic mantle) is made almost entirely of basaltic rocks, with peridotite underneath in the mantle.

Explanation: im pretty sure thats right at least

6 0
3 years ago
How many milligrams of MgI2 must be added to 257.7 mL of 0.087 M KI to produce a solution with [I−] = 0.1000 M?
lbvjy [14]

Answer:

The answer is 465.6 mg of MgI₂ to be added.

Explanation:

We find the mole of ion I⁻ in the final solution

C = n/V -> n = C x V = 0.2577 (L) x 0.1 (mol/L) = 0.02577 mol

But in the initial solution, there was 0.087 M KI, which can be converted into mole same as above calculation, equal to 0.02242 mol.

So we need to add an addition amount of 0.02577 - 0.02242 = 0.00335 mol of I⁻. But each molecule of MgI₂ yields two ions of I⁻, so we need to divide 0.00335 by 2 to find the mole of MgI₂, which then is 0.001675 mol.

Hence, the weight of MgI₂ must be added is

Weight of MgI₂ = 0.001675 mol x 278 g/mol = 0.4656 g = 465.6 mg

4 0
3 years ago
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