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3 years ago

Whats is the purpose of the

Physics

1 answer:

snow_lady [41]3 years ago

3 0

here's your correct answer.. please copy it..

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Plz help me and thx if you do!

Rina8888 [55]

I think it’s b... not sure tho sorry

3 0

3 years ago

Hello please help i’ll give brainliest

balu736 [363]

D, I hope this is correct!

6 0

3 years ago

An electron and a proton are fixed at a separation distance of 973 nm. Find the magnitude and the direction of the electric fiel

Vilka [71]

Answer:

The magnitude is: $|E|=6084.1\: N/C$

The direction of E is in the negative x-direction.

Explanation:

The electric field equation is:

$E=k\frac{Q}{r^{2}}$

Where:

Q is the charge (we can choose the electron or the proton)
r is the distance (in our case is at the midpoint 973/2 nm)
k is the Coulomb constant ( $9*10^{9}\: Nm^{2}C^{-2}$ )

Using the electron charge ( $e = -1.6*10^{-19}\: C$ )

$E=-9*10^{9}\frac{1.6*10^{-19}}{(486.5*10^{-9})^{2}}$

The magnitude is:

$|E|=6084.1\: N/C$

The direction of E is in the negative x-direction.

I hope it helps you!

6 0

3 years ago

Educación física como se puede mejorar la técnica deportiva

motikmotik

Answer:

Varíe sus entrenamientos. Para muchos atletas, los ejercicios funcionales son el nombre del juego. ...

Realice un seguimiento y mida su rendimiento durante el entrenamiento. ...

Haga de la hidratación adecuada una prioridad. ...

Dedique suficiente tiempo a la recuperación. ...

Entrena tu cerebro. ...

Alimente su cuerpo de la manera correcta. ...

Considere agregar algunos suplementos a su dieta.

Explanation:

8 0

3 years ago

The noble gases neon (atomic mass 20.1797 u) and krypton (atomic mass 83.798 u) are accidentally mixed in a vessel that has a te

vagabundo [1.1K]

Answer:

(a) Kav Ne = Kav Kr = 7.29x10⁻²¹J

(b) v(rms) Ne= 659.6m/s and v(rms) Kr= 323.7m/s

Explanation:

(a) According to the kinetic theory of gases the average kinetic energy of the gases can be calculated by:

$K_{av} = \frac{3}{2}kT$ (1)

where $K_{av}$ : is the kinetic energy, k: Boltzmann constant = 1.38x10⁻²³J/K, and T: is the temperature

From equation (1), we can calculate the average kinetic energies for the krypton and the neon:

$K_{av} = \frac{3}{2} (1.38\cdot 10^{-23} \frac{J}{K})(352.2K) = 7.29\cdot 10^{-21}J$

(b) The rms speeds of the gases can be calculated by:

$K_{av} = \frac{1}{2}mv_{rms}^{2} \rightarrow v_{rms} = \sqrt \frac{2K_{av}}{m}$

where m: is the mass of the gases and $v_{rms}$ : is the root mean square speed of the gases

For the neon:

$v_{rms} = \sqrt \frac{2(7.29 \cdot 10^{-21}J)}{20.1797 \frac{g}{mol} \cdot \frac {1mol}{6.022\cdot 10^{23}molecules} \cdot \frac{1kg}{1000g}} = 659.6 \frac{m}{s}$

For the krypton:

$v_{rms} = \sqrt \frac{2(7.29 \cdot 10^{-21}J)}{83.798 \frac{g}{mol} \cdot \frac {1mol}{6.022\cdot 10^{23}molecules} \cdot \frac{1kg}{1000g}} = 323.7 \frac{m}{s}$

Have a nice day!

3 0

3 years ago