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serious [3.7K]
3 years ago
14

What is the equivalent resistance of the circuit?

Physics
2 answers:
Zigmanuir [339]3 years ago
8 0

Answer:

5.5Ω

 

Explanation:

The circuit diagram shown is a parallel arrangement. To solve this problem for the equivalent resistance,

  R1  = 10Ω

  R2  = 20Ω

 R3 = 30Ω  

For circuits in parallel, equivalent resistance is ;

   \frac{1}{Rt}   = \frac{1}{R1}   + \frac{1}{R2}  + \frac{1}{R3}  

 Now insert the parameters and solve;

    \frac{1}{Rt}  = \frac{1}{10}   +  \frac{1}{20}  + \frac{1}{30}  

    \frac{1}{Rt}   = \frac{6 + 3 + 2}{60}  

    \frac{1}{Rt}   = \frac{11}{60}  

    Rt  = 5.5Ω

 

faltersainse [42]3 years ago
8 0

Answer: 5.45

Explanation: A P E X

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Radda [10]
Hydroelectric power is considered to be an example of multiple transfers of energy because potential energy when the water is in the reservoir turns into kinetic energy making the water move to the dam and then the dam moves into the turbine turning it to electric energy.  
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Pls help in these 2 questions
Nadya [2.5K]

Answer:

Taking forces along the plane

F cos θ - M g sin θ -100 = M a       net of forces along the plane

F = (M a + M g * .5 + 100) / .866     solving for F

F = (80 * 1.5 + 80 * 9.8 * .5 + 100) / .866 = 707 N

F = 707 N acting along the plane

Fn = F sin θ + M g cos θ       forces acting perpendicular to plane

Fn = 707 * 1/2 + 80 * 9.8 * .866 = 1030 Newtons   forces normal to plane

(this would give a coefficient of friction of 100 / 1030 = .097 = Fn)

4 0
2 years ago
Proved that<br>V = u+at<br>​
kondaur [170]

Answer:

\sf Proof \ below

Explanation:

We know that acceleration is change in velocity over time.

\sf a=\frac{\triangle v}{t}

\sf a=\frac{v-u}{t}

v is the final velocity and u is the initial velocity.

Solve for v.

Multiply both sides by t.

\sf at=v-u

Add u to both sides.

\sf at + u=v

3 0
3 years ago
Read 2 more answers
A body which has surface area 5cm² and temperature of 727°C radiates 300J of energy in one minute. Calculate it's emissivity giv
cestrela7 [59]
<h2>Answer: 0.17</h2>

Explanation:

The Stefan-Boltzmann law establishes that a black body (an ideal body that absorbs or emits all the radiation that incides on it) "emits thermal radiation with a total hemispheric emissive power proportional to the fourth power of its temperature":  

P=\sigma A T^{4} (1)  

Where:  

P=300J/min=5J/s=5W is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing 1W=\frac{1Joule}{second}=1\frac{J}{s}

\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A=5cm^{2}=0.0005m^{2} is the Surface area of the body  

T=727\°C=1000.15K is the effective temperature of the body (its surface absolute temperature) in Kelvin.

However, there is no ideal black body (ideal radiator) although the radiation of stars like our Sun is quite close.  So, in the case of this body, we will use the Stefan-Boltzmann law for real radiator bodies:

P=\sigma A \epsilon T^{4} (2)  

Where \epsilon is the body's emissivity

(the value we want to find)

Isolating \epsilon from (2):

\epsilon=\frac{P}{\sigma A T^{4}} (3)  

Solving:

\epsilon=\frac{5W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}})(0.0005m^{2})(1000.15K)^{4}} (4)  

Finally:

\epsilon=0.17 (5)  This is the body's emissivity

3 0
3 years ago
In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
Margaret [11]

Answer:

D = -4/7 = - 0.57

C = 17/7 = 2.43

Explanation:

We have the following two equations:

3C + 4D = 5\ --------------- eqn (1)\\2C + 5D = 2\ --------------- eqn (2)

First, we isolate C from equation (2):

2C + 5D = 2\\2C = 2 - 5D\\C = \frac{2 - 5D}{2}\ -------------- eqn(3)

using this value of C from equation (3) in equation (1):

3(\frac{2-5D}{2}) + 4D = 5\\\\\frac{6-15D}{2} + 4D = 5\\\\\frac{6-15D+8D}{2} = 5\\\\6-7D = (5)(2)\\7D = 6-10\\\\D = -\frac{4}{7}

<u>D = - 0.57</u>

Put this value in equation (3), we get:

C = \frac{2-(5)(\frac{-4}{7} )}{2}\\\\C = \frac{\frac{14+20}{7}}{2}\\\\C = \frac{34}{(7)(2)}\\\\C =  \frac{17}{7}\\

<u>C = 2.43</u>

5 0
3 years ago
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