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sweet-ann [11.9K]
3 years ago
7

g A ball is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. The ball rises to a height eq

ual to the asteroid's radius and then falls straight down toward the surface of the asteroid. What forces, if any, act on the ball while it is on the way up
Physics
1 answer:
Anni [7]3 years ago
4 0

Answer:

Only a decreasing gravitational force that acts downward

Explanation:

The gravitational force is the gravitational pull which attract a mass of smaller size by the mass of a bigger size.  It is the force which attract two masses close to each other.

In the context, when a ball is tossed up from the surface of an asteroid that have no atmosphere, the ball rises up and then falls back to the surface of the asteroid. The ball falls back because the gravitational pull of the asteroid pulls back the ball to its surface. Thus a decreasing gravitational force acts on the ball in the downward direction while the ball is in its way up.  

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Which of the following accurately describes the way in which a muscle moves?
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<h3><u>Answer</u>;</h3>

B. When actin filaments are pulled toward the center of the sarcomere, the fiber shortens.

<h3><u>Explanation;</u></h3>
  • <em><u>The events of muscle fiber shortening occurs with in the sacromeres in the fibers. </u></em>
  • <em><u>Contraction of striated muscle fibers takes place as the sacromeres shorten as myosin heads pull on the actin filaments.</u></em>
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3 years ago
When this circuit is closed, which way do the electrons flow?
gizmo_the_mogwai [7]

Answer:

from the positive end of the battery through the capacitor through the resistors to the negative end...

Current flows from higher potential (+) to lower potential (-)..

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3 years ago
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Newton’s first law because the airplane needs space to fully stop due to its inertia
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You lift a large bag of flour from the floor to a 2.5m high counter, doing 400J of work in 2 seconds. How much force did you app
oksian1 [2.3K]
<h2>The man have to apply force of 160 N</h2>

Explanation:

The work done to lift the bag of weight mg through height 2.5 m is 400 J

The work done can be found by relation  W = mg x h

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Therefore the man have to apply the force of 160 N

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Independent practice
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Explanation:

formula: <u>Mass</u>

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160÷0.1=1600 kg/m

2c) m = 220 kg V = 0.02m³

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20÷ 0.025=800 kg/m

Challenge: A rectangular concrete slab is 0.80m long, 0.60 m wide and 0.04m thick. Calculate its volume in m³.

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