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uysha [10]
3 years ago
11

A potter's wheel moves from rest to an angu-

Physics
1 answer:
dusya [7]3 years ago
8 0

Answer:

angular acceleration =<u>final angular speed + initial angular speed</u>

                                                                     time

                                  =<u>0.6283rad/s +0</u>

                                            24.6s

                                   =0.6283/24.5

                                   =0.025rad/s^2

Explanation:

first angular speed is equal to angular velocity and we will convert the unit to rad/s so 1rev/sec=6.283rad/s then angular acceleration is the rate at which the angular velocity changes with the time we have the final angular velocity,initial angular velocity and time now substitute the numbers in the formula and the value will be 0.025 rad per seconde square

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Which is directly proportional to your weight on a planet's surface?
Mila [183]

Answer:

Weight is directly proportional to our mass and acceleration due to gravity of that planet

5 0
3 years ago
what will happen to the fieldof view for each resultant magnification as you change objectives from 4 to 10 to 43
jonny [76]

Answer:

The field of view is reduced.

Explanation:

Given that,

The field of view for every resultant magnification like you change objectives from 4 to 10 to 43.

We know that,

Field of view :

When the view is observed at a point in a defined field then these field called field of view.

The normal angle of  field of view is 90°.

The formula of field of view is define as,  

field\ of\ view = \dfrac{field\ number}{magnification}

We can say that,

The field of view is inversely proportional to the magnification.

When magnification is low then field of view will be large.

When magnification is higher then field of view will be small .

According to question,  

When the magnification adjust from 4 to 10 to 43, the field of view is reduced.    

Hence, The field of view is reduced.

7 0
3 years ago
A mixture of iron and sulfur can be separated by
s2008m [1.1K]

Answer:

magnetic attraction

Explanation:

i think so..

3 0
3 years ago
Read 2 more answers
Temperature flows from __ to __ temperatures
timama [110]

Answer:hot to cold

Explanation:

Temperature flow from hot to cold temperatures

8 0
3 years ago
What is the magnitude (in N/C) and direction of an electric field that exerts a 3.50 ✕ 10−5 N upward force on a −1.55 µC charge?
IRISSAK [1]

Answer:

The magnitude of electric field is  22.58 N/C

Solution:

Given:

Force exerted in upward direction, \vec{F_{up}} = 3.50\times 10^{- 5} N

Charge, Q = - 1.55\micro C = - 1.55\times 10^{- 6} C

Now, we know by Coulomb's law,

F_{e} = \frac{1}{4\pi\epsilon_{o}\frac{Qq}{R^{2}}

Also,

Electric field, E = \frac{1}{4\pi\epsilon_{o}\frac{q}{R^{2}}

Thus from these two relations, we can deduce:

F = QE

Therefore, in the question:

\vec{E} = \frac{\vec F_{up}}{Q}

\vec{E} = \frac{3.50\times 10^{- 5}}{- 1.55\times 10^{- 6}}

\vec{E} = - 22.58 N/C

Here, the negative side is indicative of the Electric field acting in the opposite direction, i.e., downward direction.

The magnitude of the electric field is:

|\vec{E}| = 22.58\ N/C

6 0
3 years ago
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