Answer:
Explanation:
Given that,
First Capacitor is 10 µF
C_1 = 10 µF
Potential difference is
V_1 = 10 V.
The charge on the plate is
q_1 = C_1 × V_1 = 10 × 10^-6 × 10 = 100µC
q_1 = 100 µC
A second capacitor is 5 µF
C_2 = 5 µF
Potential difference is
V_2 = 5V.
Then, the charge on the capacitor 2 is.
q_2 = C_2 × V_2
q_2 = 5µF × 5 = 25 µC
Then, the average capacitance is
q = (q_1 + q_2) / 2
q = (25 + 100) / 2
q = 62.5µC
B. The two capacitor are connected together, then the equivalent capacitance is
Ceq = C_1 + C_2.
Ceq = 10 µF + 5 µF.
Ceq = 15 µF.
The average voltage is
V = (V_1 + V_2) / 2
V = (10 + 5)/2
V = 15 / 2 = 7.5V
Energy dissipated is
U = ½Ceq•V²
U = ½ × 15 × 10^-6 × 7.5²
U = 4.22 × 10^-4 J
U = 422 × 10^-6
U = 422 µJ
Answer:
The force on the proton will be twice in comparison with the force experienced by the electron.
Explanation:
The magnetic force acting on the moving charge particle is perpendicular to the velocity as well as the magnetic field. The factors upon which the magnitude of the force is depending and proportional are as follows:
1 Magnitude of the charge particle.
2 Magnitude of the velocity of moving charge.
3 Magnitude of magnetic field.
4 Sine of angle between the velocity and magnetic field.
As far as direction is concerned, it can be find out by right hand rule.
Lets consider,
Speed of electron = Ve
Speed of proton vp= 2ve
Magnitude of the force F = qvBsin∅
Force acting on electron Fe = qe.ve.Bsin∅
Force acting on proton Fp = qp.vp.Bsin∅
Fp = -2 qe.ve.Bsin∅
Fp = -2Fe
Negative sign shows the direction of Force on proton is opposite to the direction of force on electron.
B is the anwer hoou[ that hrtoj
Answer:
Explanation:
In this case we have to use the Principle of conservation of Momentum:
<em>This principle says that in a system the total momentum is constant if no external forces act in the system. The formula is:</em>
<em>Where:</em>
Mass of the first object.
Mass of the second object.
Initial velocity of the first object.
Initial velocity of the second object.
Final velocity of the first object.
Final velocity of the second object.
In <u>this problem</u> we have:
Observation: 
Is because the system has the same initial velocity.
First we have to find 
,
We can rewrite it as:
Replacing with the data:
We found the final velocity of the cart, but the problem asks for the resulting change in the cart speed, this means:
Then, the resulting change in the cart speed is:
1 Days to Seconds = 86400 70 Days to Seconds = 6048000
2 Days to Seconds = 172800 80 Days to Seconds = 6912000
3 Days to Seconds = 259200 90 Days to Seconds = 7776000
4 Days to Seconds = 345600 100 Days to Seconds = 8640000
