1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bess [88]
3 years ago
9

When you are standing on Earth, orbiting the Sun, and looking at a broken cell phone on the ground, there are gravitational pull

s on the cell phone from you, the Earth, and the Sun. Rank the gravitational forces on the phone from largest to smallest. Assume the Sun is roughly 109 times further away from the phone than you are, and 1028 times more massive than you. Rank the following choices in order from largest gravitational pull on the phone to smallest. To rank items as equivalent, overlap them.
a. Pull phone from you
b. Pull on phone from earth
c. Pull on phone from sun
Physics
1 answer:
Mandarinka [93]3 years ago
5 0

Answer:

The answer is "Option b, c, and a".

Explanation:

Here that the earth pulls on the phone, as it will accelerate towards Earth when we drop it.

We now understand the effects of gravity:

F \propto  M\\\\F\propto  \frac{1}{r^2}\\\\or\\\\F \propto  \frac{M}{r^2}\\\\Sun (\frac{M}{r^2}) = \frac{10^{28}}{(10^9)^2} = 10^{10}

The force of the sun is, therefore, 10^{10} times greater and the proper sequence, therefore, option steps are:

b. Pull-on phone from earth

c. Pull-on phone from sun

a. Pull phone from you

You might be interested in
What is 800,000,000 meters in scientific notation
Paladinen [302]

8 x 10^8 = 800,000,000

In Scientific Notation, your goal is to get your the number you're multiplying by 10 (8 in this case) to be between 0 and 10.  Therefore, you would NOT have 80 x 10^7 because 80 is not between 0 and 10.

7 0
3 years ago
Read 2 more answers
The vapor pressure of benzene, C6H6, is 40.1 mmHg at 7.6°C. What is its vapor pressure at 60.6°C? The molar heat of vaporization
ANEK [815]

Answer:

The vapor pressure at 60.6°C is 330.89 mmHg

Explanation:

Applying Clausius Clapeyron Equation

ln(\frac{P_2}{P_1}) = \frac{\delta H}{R}[\frac{1}{T_1}- \frac{1}{T_2}]

Where;

P₂ is the final vapor pressure of benzene = ?

P₁ is the initial vapor pressure of benzene = 40.1 mmHg

T₂ is the final temperature of benzene = 60.6°C = 333.6 K

T₁ is the initial temperature of benzene = 7.6°C = 280.6 K

ΔH is the molar heat of vaporization of benzene = 31.0 kJ/mol

R is gas rate = 8.314 J/mol.k

ln(\frac{P_2}{40.1}) = \frac{31,000}{8.314}[\frac{1}{280.6}- \frac{1}{333.6}]\\\\ln(\frac{P_2}{40.1}) = 3728.65 (0.003564 - 0.002998)\\\\ln(\frac{P_2}{40.1}) = 3728.65  (0.000566)\\\\ln(\frac{P_2}{40.1}) = 2.1104\\\\\frac{P_2}{40.1} = e^{2.1104}\\\\\frac{P_2}{40.1} = 8.2515\\\\P_2 = (40.1*8.2515)mmHg = 330.89 mmHg

Therefore, the vapor pressure at 60.6°C is 330.89 mmHg

6 0
4 years ago
Read 2 more answers
In deep space, there is very little friction. Once they launch a probe into deep space, where there are no external forces actin
zimovet [89]
<span>the scientists want the probe to stop immediately and move at constant velocity.
HAPPY VALENTINES </span>
8 0
4 years ago
Read 2 more answers
A 10kg oil is heated by a source of heat that supplies 800J of heat every minute. Calculate The heat added to oil after 30 minut
goblinko [34]

Answer:

4,200 joules per kilogram per degree Celsius

Explanation:

The specific heat capacity of a material is the energy required to raise one kilogram (kg) of the material by one degree Celsius (°C). The specific heat capacity of water is 4,200 joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200 J to raise the temperature of 1 kg of water by 1°C.

4 0
2 years ago
You measure the power delivered by a battery to be 4.26 W when it is connected in series with two equal resistors. How much powe
gtnhenbr [62]

Answer:

<em>The power delivered by the battery is 17.04 W</em>

Explanation:

Power through a circuit is given as

P = IV    ....1

where P is the power

I is the current through the circuit

V is the voltage through the circuit

The voltage in a circuit is given as

V = IR    ....2

Let us take the value of each resistor as equal to R

when connected in series, the total resistance will be

R_{t} = R + R = 2R

If we assume constant voltage through the circuit, then from equation 2, the current in this case is

I = V/2R

If the resistors are connected in parallel, then the total resistance will be

\frac{1}{R_{t} } = \frac{1}{R} +

R_{t} = R/2

The current in this case will be increased since the resistance is reduced

I = 2V/R

comparing the two situations, we can see that the current increased when connected in parallel to a ratio of

\frac{2V}{R} ÷  \frac{V}{2R} =  

This means that the current increased 4 times

From equation 1, we can see that electrical power is proportional to the current at a constant voltage, therefore, the power will also increase by four times to

P = 4 x 4.26 = <em>17.04 W</em>

3 0
4 years ago
Other questions:
  • What are some of the challenges that face wave energy production?
    14·2 answers
  • While Calvin is doing a physics experiment outside with a radar gun, he notices that after three seconds a car reaches a speed o
    9·1 answer
  • A hot air balloon is hovering in the air when it drops a 40 Kg food package to some lost golfers. If the package is dropped from
    12·1 answer
  • If a 100 N net force act on a 50-kg car, what will the acceleration be
    5·1 answer
  • Which best describes a force?
    12·2 answers
  • Which kind of force do you exert on an object when you pull it toward you?
    10·2 answers
  • A)topirea ghetii este un fenomen...
    10·1 answer
  • What causes diffraction that results in a fuzzy glow around a full moon?
    15·2 answers
  • What task requires the most work, lifting a 12-kg sack 2 meters or lifting a 25-kg sack 1 meter?
    8·1 answer
  • Label each of the front symbols below and describe what kind of weather they can bring.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!