Question

Please help me, Engineering.

Answer 1

Answer:

15. R = R₁ + R₂ + R₃

16.  $R = \dfrac{1}{R_1} +\dfrac{1}{R_2} = \dfrac{R_2 + R_1}{R_1 \cdot R_2}$

Explanation:

15. The equation for the sum of resistances arranged in series is given as follows;

$R_{Network}$ (Series) = R₁ + R₂ + R₃ + ... + $R_N$

Therefore, the equation for the total resistance, 'R' of 3 series resistors is given as follows;

R = R₁ + R₂ + R₃

Where;

R₁, R₂, and R₃ are the three resistances arranged in series

16. The equation for the sum of resistances arranged in parallel is given as follows;

$R_n = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} + ... + \dfrac{1}{R_n}$

Therefore, the total resistance, R, of two resistance arranged in parallel is given as follows;

$R = \dfrac{1}{R_1} +\dfrac{1}{R_2} = \dfrac{R_2 + R_1}{R_1 \cdot R_2}$