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marin [14]
3 years ago
8

Please help me, Engineering.

Engineering
1 answer:
antiseptic1488 [7]3 years ago
8 0

Answer:

15. R = R₁ + R₂ + R₃

16.  R = \dfrac{1}{R_1} +\dfrac{1}{R_2}  = \dfrac{R_2 + R_1}{R_1 \cdot R_2}

Explanation:

15. The equation for the sum of resistances arranged in series is given as follows;

R_{Network} (Series) = R₁ + R₂ + R₃ + ... + R_N

Therefore, the equation for the total resistance, 'R' of 3 series resistors is given as follows;

R = R₁ + R₂ + R₃

Where;

R₁, R₂, and R₃ are the three resistances arranged in series

16. The equation for the sum of resistances arranged in parallel is given as follows;

R_n = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dfrac{1}{R_3} + ... + \dfrac{1}{R_n}

Therefore, the total resistance, R, of two resistance arranged in parallel is given as follows;

R = \dfrac{1}{R_1} +\dfrac{1}{R_2}  = \dfrac{R_2 + R_1}{R_1 \cdot R_2}

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How would I find the Voltage across the open circuit
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Answer:

  Vab = 80V

Explanation:

The only current flowing in the circuit is supplied by the 100 V source. Its only load is the 40+60 ohm series circuit attached, so the current in that loop is (100V)/(40+60Ω) = 1A. That means V1 = (1A)(60Ω) = 60V.

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2 years ago
It is given that 50 kg/sec of air at 288.2k is iesntropically compressed from 1 to 12 atm. Assuming a calorically perfect gas, d
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The exit temperature is 586.18K and  compressor input power is 14973.53kW

Data;

  • Mass = 50kg/s
  • T = 288.2K
  • P1 = 1atm
  • P2 = 12 atm

<h3>Exit Temperature </h3>

The exit temperature of the gas can be calculated isentropically as

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^\frac{y-1}{y}\\ y = 1.4\\ C_p= 1.005 Kj/kg.K\\

Let's substitute the values into the formula

\frac{T_2}{T_1} = (\frac{P_2}{P_1})^\frac{y-1}{y} \\\frac{T_2}{288.2} = (\frac{12}{1})^\frac{1.4-1}{1.4} \\ T_2 = 586.18K

The exit temperature is 586.18K

<h3>The Compressor input power</h3>

The compressor input power is calculated as

P= mC_p(T_2-T_1)\\P = 50*1.005*(586.18-288.2)\\P= 14973.53kW

The compressor input power is 14973.53kW

Learn more on exit temperature and compressor input power here;

brainly.com/question/16699941

brainly.com/question/10121263

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A battery is connected to a resistor. Increasing the resistance of the resistor will __________. A battery is connected to a res
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Answer: the increase in the external resistor will affect and decrease the current in the circuit.

Explanation: A battery has it own internal resistance, r, and given an external resistor of resistance, R, the equation of typical of Ohm's law giving the flow of current is

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Where IR is the potential difference flowing in the external circuit and Or is the lost voltage due to internal resistance of battery. From (1)

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