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Schach [20]
3 years ago
14

Calculate the mass in grams of each sample. 4.68×1020 H2O2 molecules

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
7 0
24= y2k* - 2x H202 grams in mass
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The absorbance of a 0.45 mol dm–3 solution of an aromatic amino acid, 3.0 cm thick is 0.22 at a wavelength of 295 nm:
34kurt

Explanation:

a) Using Beer-Lambert's law :

Formula used :

A=\epsilon \times C\times l

where,

A = absorbance of solution = 0.22

C = concentration of solution = 0.45 mol/dm^3=0.45 mol/L=0.45 M

1 dm^3 = 1 L

l = length of the cell = 3.0 cm

\epsilon = molar absorptivity of this solution = ?

Now put all the given values in the above formula, we get the molar absorptivity of this solution.

0.22=\epsilon \times (0.45 M)\times (3.0 cm)

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b) A=\log \frac{I_o}{I_t}

T=\frac{I_t}{I_o}

A=\log \frac{1}{T}

A = 2 × 0.22 =0.44

I_o,I_t = Intensities of Incident light and transmitted light respectively

T = Transmittance

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T = 0.3630

c) I_o=x

I_t=65\% of x=0.65 x

Thickness of cell = l' =?

c = 0.75 mol/ dm^3=0.75 mol/L=0.75 M

A=\log \frac{I_o}{I_t}=\epsilon \times C\times l

\log \frac{x}{0.65x}=0.163 M^{-1}cm^{-1}\times 0.45 M\times l'

l' = 1.53 cm

d) No, we cannot calculate the absorbance at 590 nm from the given data. This is because absorbance at this wavelength  can be observe experimentally.

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4 years ago
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Since we refrigerate milk, it would be cooler than the room temperature, which standard norm is 25°C. So the milk has to be colder than the room temperature. Therefore, our answer is A.

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Answer:

c, hydrochloric acid

Explanation:

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Ionic bonds are between nonmetals and metals.  The electrons are transferred in these bonds.

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