Question

25.00 grams of sodium chloride reacts with an excess

Answer 1

Mass of HCl produced :15.59 g

Further explanation

Reaction

2NaCl + H₂SO₄ → 2HCl + Na₂SO₄

Excess = H₂SO₄

Limiting = NaCl

mass NaCl = 25 g

mol NaCl(MW=58.5 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{25}{58.5}=0.427$

From the equation, mol ratio NaCl : HCl = 2 : 2, so mol HCl = mol NaCl =0.427

Mass of HCl(MW=36.5 g/mol) :

$\tt mass=mol\times MW\\\\mass=0.427\times 36.5\\\\mass=15.59~g$