Answer:
Option b. Dark spot
Explanation:
Michelson interferometer gives the path difference of the light as path difference, d as twice the distance moved or covered by the mirror , x and is given as:
d= 2x
Since, its an even multiple, we obtain a bright fringe
now, when the move half the distance, i.e.,
Therefore, the path difference for half the distance is:
d = x
As it is clear that its an odd multiple which correspond to dark spot as the final image
Answer:
The work done is
Explanation:
Work is defined as the product of force and distance moved in the direction of application of force.
Given Data
distance S= 230m
force F= 140 N
Mass of car m= 1140 kg
Applying the formula for work done we have
The work done by pushing the car for a distance of is
a) The work done is 920 J
b) The work done is 5200 J
Explanation:
a)
In this first part of the problem, the crate is moved horizontally at constant speed.
The work required in this case is given by
where
F is the magnitude of the force applied
d is the displacement of the crate
is the angle between the direction of the force and of the displacement
Here the crate is moved at constant speed: this means that the acceleration of the crate is zero, and so according to Newton's second law, the net force on the crate is zero: this means that the force applied, F, must be equal to the force of friction (but in opposite direction), so
F = 230 N
The displacement is
d = 4.0 m
And the angle is , since the force is applied horizontally. Therefore, the work done is
b)
In this case, the crate is moved vertically. The force that must be applied to lift the crate must be equal to the weight of the crate (in order to move it a constant speed), therefore
F = W = 1300 N
The displacement this time is again
d = 4.0 m
And the angle is , since the force is applied vertically, and the crate is moved also vertically. Therefore, the work done on the crate this time is
Learn more about work:
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