Augmentation or deduction of kinetic energy will tell you if any work is done here.
Explanation:
Here,
E<sub>k0</sub>=0.5mv<sub>0</sub><sup>2</sup>=16,537.5 J
E<sub>kf</sub>=0.5mv<sub>f</sub><sup>2</sup>=194,400 J
Now,
E<sub>k0</sub> - E<sub>kf</sub> = 177,862.5 J
Hence, work is done.
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Answer:
The error in tapping is ±0.02828 ft.
Explanation:
Given that,
Distance = 200 ft
Standard deviation = ±0.04 ft
Length = 100 ft
We need to calculate the number of observation
Using formula of number of observation
Put the value into the formula
We need to calculate the error in tapping
Using formula of error
Put the value into the formula
Hence, The error in tapping is ±0.02828 ft.
Answer:
a) 1511 MW
b) 44%
Explanation:
The thermal power will be the electric power plus the heat taken away by the cooling water.
Qt = P + Qc
The heat taken away by the water will be:
Qc = G * Cp * (t1 - t0)
The Cp of water is 4180 J/(kg K)
The density of water is 1 kg/L
Then
G = 1.17 * 10^8 L/h * 1 kg/L * 1/3600 h/s = 32500 kg/s
Now we calculate Qc
Qc = 32500 * 4180 * (29.8 - 23.6) = 842*10^6 W = 842 MW
The total thermal power then is
Qt = 669 + 842 = 1511 MW
The efficiency is
η = P / Qt
η = 669 / 1511 = 44%
Answer: rp/re= me/mp= 544 * 10^-6.
Explanation: To calculate this problem we have to consider the circular movement by the electron and proton inside a magnetic field.
Then the dynamic equation for the circular movement is given by:
Fcentripetal= m*ω^2.r
q*v*B=m*ω^2.r
we write this for each particle then we have the following:
q*v*B=me* ω^2*re
q*v*B=mp* ω^2*rp
rp/re=me/mp=9.1*10^-31/1.67*10^-27=544*10^-6
Answer:
a piece of equipment with moving parts that does work when it is given power from electricity, gasoline, etc.
Explanation:
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