H has a charge of +1, and O has a charge of -2. In this case, C in C7H12 would have a charge of -12/7 to balance it out. Meanwhile, C in CO2 would have a charge of +4. Since the charge of C went from negative to positive, this implies that C lost electrons, which is indicative of oxidation (and thus it was the reducing agent). Therefore, C7H12 was the reducing agent, while O2 was the oxidizing agent.
The correct answer here is A - An atom with a positive charge has more
protons than electrons. In the other instances the atom would have a
negative charge.
<span>Microscopic foreign particles that droplets form on is called the hygroscopic nuclei. The particles are already present in the air in the form of dust, salt from seawater evaporation and combustion residue. Together the particles begin the forming process of droplets.</span>
KI-starch paper allows the detection of strong oxidizers such as nitrite. It is used here to control diazotization of 4-nitroaniline. Nitrite oxidizes potassium iodide in order to form elemental iodine which reacts with starch to a blue-violet complex. With KI-starch paper, enough sodium nitrite is added to produce nitrous acid, which <span>then will react with 4-nitroaniline to form a diazonium salt.</span>