All categories

3 years ago

It takes 500 W of power to move an object 96 m in 12 s. What force is being applied to the object?

Physics

2 answers:

agasfer [191]3 years ago

4 0

Answer: 125/24 N

Explanation:

The work can be calculated with W = Fs

Where W = work

F = force

and s = displacement

Let's set up the equation:

500w = F * 96m

$\frac{500}{96}$ = 125/24 or roughly 5.2 N of force

slava [35]3 years ago

4 0

Answer:

Explanation:

Power, by definition, is the amount of work per unit of time. We arent given work in this question, but we can find it because work is how much force per unit of distance.

$P=\frac{W}{t_f-t_i} =\frac{F*d}{t_f-t_i}$

Plug in all the values, and its algebra at this point

$500=\frac{F*96}{12}$

6000 = 96F

F = 62.5 Newtons

You might be interested in

Determine the MA based on the diagram below.

artcher [175]

There are two things that you should remember while dealing with the "Lever Mechanical Advantage" problems:

1) The Effort Arm;
2) The Resistance Arm.

Some books label the Effort Arm as in-lever arm and the Resistance Arm as out-lever arm. (Physics Jargon that you need to remember in order to solve problems)

The Effort Arm is that "part" of the lever where the force can be applied. The Resistance Arm is where some mass is placed. In the diagram, as you can see, the mass is placed on one arm of the lever. Therefore, it is the Resistance Arm.

Now the formula for the "Mechanical Advantage(MA)" is:
$MA = \frac{L_{e} }{ L_{r} }$

Where $L_{e}$ is the length of the Effort Arm(the subscript "e" stands for Effort), and $L_{r}$ stands for the length of the Resistance Arm(here "r" stands for Resistance).

Plug in the values:

$L_{e}$ = 15m.
$L_{r}$ = 7m.

Therefore, $L_{e}$ / $L_{r}$ = 15/7 = 2.143 = MA

The correct answer is option C(2.14).

-i

3 0

3 years ago

Read 2 more answers

What is the speed of sound for noise that travels 2 km in 5.8

earnstyle [38]

Answer:

2.9

Explanation:

average speed=distance/time taken

=2/5.8

=2.9

8 0

3 years ago

The capacitance of the variable capacitor of a radio can be changed from 100 to 350 pF by turning the dial from 0° to 180°. With

tangare [24]

Answer:

0.7 mJ

Explanation:

Identify the unknown:

The work required to turn the dial from 180° to 0°

List the Knowns:

Capacitance when the dial is set at 180°: C = 350 pF = 350 x 10^-12 F Capacitance when the dial is set at 0°: C = 100 pF = 100 x 10^-12 F

Voltage of the battery: V = 130 V

Set Up the Problem:

Energy stored in a capacitor:

U_c=1/2*V^2*C

=1/2*Q^2/C

When the dial is set at 180°:

U_c=1/2*(130)^2*350*10^-12=10^-4

Q=√2*U_c*C=4*10^-7

When the dial is set at 0°:

U_c=1/2*(4*10^-7)^2/100*10^-12

=8*10^-4 J

Solve the Problem:

ΔU_c=7*10^-4 J

=0.7 mJ

note:

there maybe error in calculation but method is correct

4 0

3 years ago

Read 2 more answers

One of the foci for the moon's orbit would be the

suter [353]

The question is oversimplified, and pretty sloppy.

Relative to the Earth . . .
The Moon is in an elliptical orbit around us, with a period of
27.32... days, and with the Earth at one focus of the ellipse.

Relative to the Sun . . .
The Moon is in an elliptical orbit around the Sun, with a period
of 365.24... days, and with the Sun at one focus of the ellipse,
and the Moon itself makes little dimples or squiggles in its orbit
on account of the gravitational influence of the nearby Earth.

I'm sorry if that seems complicated. You know that motion is
always relative to something, and the solar system is not simple.

5 0

3 years ago

Read 2 more answers

A remote Internet Web page may sometimes reach your computer by going through a geostationary satellite orbiting approximately 3

soldier1979 [14.2K]

Answer:

0.24 seconds

Explanation:

The signal will reach the computer at light speed = $3\times 10^8\ m/s$

Distance between the satellite and the computer = $3.6\times 10^7m$

Since, the bodies have no acceleration relative to each other we use the following formula

Time = Distance / Time

$\text{Time}=\frac{3.6\times 10^7}{3\times 10^8}\\\Rightarrow \text{Time}=0.12\ s$

One way delay would be at least 0.12 seconds.

But when you click on a link to open a website this signal has to be first sent to the satellite then the satellite would have to send the required signal back to the computer.

Hence, the minimum time delay would be 0.12+0.12 = 0.24 seconds

3 0

3 years ago