The General Equation of Alkane is as follow,
CnH₂n₊₂ ------- (1)
As m/z = 380
So,
CnH₂n₊₂ = 380
Or,
12n+ 1₂n₊₂ = 380
12n+ ₂n ₊ ₂ = 380
14n ₊ ₂ = 380
14n = 380 - 2
14n = 378
n = 378 / 14
n = 27
Now, putting value of n in eq. 1
C₂₇H₍₂₇ₓ₂₎₊₂
C₂₇H₅₆
Result:
C = 27
H = 56
Answer:
ionic bonds in the solute are broken and new ion-dipose forces in the solution are formed
Explanation:
Answer:
(1) 0.035 × 10²³
Explanation:
Step 1: Calculate the mass of Fe in 100 g of Haemoglobin
Haemoglobin contains 0.33% Fe, that is, there are 0.33 g of Fe per 100 grams of Haemoglobin.
100 g Hb × 0.33 g Fe/100 g Hb = 0.33 g Fe
Step 2: Convert 0.33 g of Fe to moles
We will use the molar mass of Fe (55.85 g/mol).
0.33 g × 1 mol/55.85 g = 5.9 × 10⁻³ mol
Step 3: Convert 5.9 × 10⁻³ moles of Fe to atoms
We will use Avogadro's number.
5.9 × 10⁻³ mol × 6.02 × 10²³ atoms/1 mol = 3.5 × 10²¹ atoms (= 0.035 × 10²³)
Answer:
29.575%
Explanation:
Data provided:
Calories taken in daily diet = 2000
Recommended amount of fat = 65 grams
Average number of calories for fat = 9.1 calories / g
Thus,
Number of calories in the diet with average number of calories for fat
= Recommended amount of fat × Average number of calories for fat
= 65 × 9.1
= 591.5 calories
Therefore,
the percentage of calories in his diet supplied = ( 591.5 / 2000 ) × 100
= 29.575%
Answer:
NaOH₂2CO3
Explanation:yes i know it is not a Balinese equation