Answer:
Molality = 1.428m
Explanation:
Molality, m, is an unit of concentration defined as the ratio between moles of solute and kg of solvent:
Molality: Moles solute / kg solvent.
In the problem, water is the solvent (Is the compound in the higher quantity) whereas NaNO₃ is the solute.
Moles of solute: 0.3355moles NaNO₃.
Kg solvent:
Thus, molality of the solution is:
Molality = 0.3355 moles NaNO₃ / 0.2350kg
<h3>Molality = 1.428m</h3>
Answer:
-24.76 kJ/g; -601.8 kJ/mol
Explanation:
There are two heat flows in this experiment.
Heat from reaction + heat absorbed by calorimeter = 0
q1 + q2 = 0
mΔH + CΔT = 0
Data:
m = 0.1375 g
C = 3024 J/°C
ΔT = 1.126 °C
Calculations:
0.1375ΔH + 3024 × 1.126 = 0
0.1375ΔH + 3405 = 0
0.1375ΔH = -3405
ΔH = -24 760 J/g = -24.76 kJ/g
ΔH = -24.76 kJ/g ×24.30 g/mol = -601.8 kJ/mol
Answer:
At 10 ∘C , the solubility of potassium chloride is measured to be 31.2⋅g per 100⋅g of water.
Explanation:
Answer:
use this formula it will help u .
Explanation:
If 60 ml of ethanol is diluted to a final volume of 400 ml, you create a 35 % ethanol solution.
First, realize that you creating a solution with that contains a polar solute (ethanol) with a polar solvent (water). Remember that "like dissolves like."
If you pour 60 ml of ethanol in a volumetric flask, you add 340 ml of water to dilute this solution to a final volume of 400 ml.
Volumetric flasks are designed to make or dilute solutions to specified final volume.
Since you have 60 ml of ethanol in a total solution of 400 ml, the percentage of ethanol is 35 %.
This result is obtained in the following manner.
ml/400. ml. = .35
.35 x 100% = 35 %
