All categories

2 years ago

The electron configuration below applies to which element? 1s2 2s2 2p6 3s2 3p1

Chemistry

1 answer:

zvonat [6]2 years ago

6 0

Aluminum! hope this helps

You might be interested in

I will give brainiest please help

gizmo_the_mogwai [7]

Answer: D and A

Explanation: <u>D</u> cuz you need water to have good soil and <u>A</u> cuz you get better soil if its warm. (: ( 'u' ) ( 'U' )

4 0

2 years ago

Read 2 more answers

An ion of which element has a larger radius than an atom of the same element?

suter [353]

An ion of chlorine element has a larger radius than an atom of the same element. It has a negative charge.

7 0

3 years ago

Consider the following reaction: C2H4(g) + H2O(g) ⇌ C2H5OH(g) ΔHo = -45.8 kJ/mol At 298K the equilibrium constant, KP, for this

Ber [7]

Answer:

ΔG = 2721.891 J/mol

Explanation:

C2H4(g) + H2O(g) ↔ C2H5OH(g)

∴ ΔH°rxn = - 45.8 KJ/mol

∴ Kp = 28.5

If p(C2H4) = p(H2O) = p(C2H5OH) = 3.0 atm ⇒ ΔG°rxn = ?

⇒ Kp = (PC2H5OH/P*) / (PC2H4/P*)(PH2O/P*)

∴ P* = 1 atm

⇒ Kp = (3 atm) / (3 atm)(3 atm) = 0.33

Kp = e∧( - ΔG/RT)

⇒ Ln Kp = - ΔG/RT

⇒ ΔG = - RT LnKp

∴ T = 298 K

∴ R = 8.314 J/mol.K

⇒ ΔG = - ((8.314 J/mol.K)(298 K)) Ln(0.33)

⇒ ΔG = 2721.891 J/mol

3 0

2 years ago

ZnCI2 + H2SO4 = ZnSO4 + HCI

Stolb23 [73]

Answer:

wat

Explanation:

4 0

2 years ago

Read 2 more answers

As a scuba diver descends under water, the pressure increases. At a total air pressure of 2.71 atm and a temperature of 25.0 C,

Anettt [7]

Answer:

The molar solubility of nitrogen gas is $1.32\times 10^{-3}mol/L$ .

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{N_2}=K_H\times p_{liquid}$

where,

$K_H$ = Henry's constant = $6.26\times 10^{-4}mol/L.atm$

$p_{N_2}$ = partial pressure of nitrogen gas

Total air pressure = P = 2.71 atm

Percentage of nitrogen in air = 78.09%

Mole fraction of nitrogen , $\hi_{N_2}= 0.7809$

$p_{N_2}=P\times \chi_{N_2}=2.71 atm\times 0.7809$

Putting values in above equation, we get:

$C_{N_2}=6.26\times 10^{-4}mol/L.atm\times 2.71 atm\times 0.7809\\\\C_{N_2}=1.32\times 10^{-3}mol/L$

Hence, the molar solubility of nitrogen gas is $1.32\times 10^{-3}mol/L$ .

6 0

2 years ago