All categories

3 years ago

State how the sun transfers energy to earth

2 answers:

Nookie1986 [14]3 years ago

6 0

The sun transfers energy to Earth in the form of electromagnetic radiation.
That includes radio waves, heat, light, ultraviolet, and X-ray energy.

Mashutka [201]3 years ago

6 0

Radiation is the transfer of heat energy through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the Earth from the sun is in the form of visible light. Light is made of waves of different frequencies.

You might be interested in

I NEED HELP ASAP!!!

Savatey [412]

I think option C is correct..hope it helps

3 0

2 years ago

Read 2 more answers

A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication

koban [17]

Answer:

r = 4.24x10⁴ km.

Explanation:

To find the radius of such an orbit we need to use Kepler's third law:

$\frac{T_{1}^{2}}{T_{2}^{2}} = \frac{r_{1}^{3}}{r_{2}^{3}}$

<em>where T₁: is the orbital period of the geosynchronous Earth satellite = 1 d, T₂: is the orbital period of the moon = 0.07481 y, r₁: is the radius of such an orbit and r₂: is the orbital radius of the moon = 3.84x10⁵ km. </em>

From equation (1), r₁ is:

$r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}$

$r_{1} = 3.84\cdot 10^{5} km \sqrt[3] {(\frac{1 d}{0.07481 y \cdot \frac{365 d}{1 y}})^{2}}$

$r_{1} = 4.24 \cdot 10^{4} km$

Therefore, the radius of such an orbit is 4.24x10⁴ km.

I hope it helps you!

3 0

3 years ago

A sound wave has a speed of 345 m/s and a wavelength of 4.15 meters. What is the frequency of this wave?

Debora [2.8K]

Answer:

83 hertz

OPTION A

Explanation:

$wavelength = \frac{speed}{frequency}$

Given

wavelength=4.15m

speed=345 m/s

$frequency = \frac{speed}{wavelength} = \frac{345}{4.15}$

$frequency = 83 \: hertz$

I hope it helped you

5 0

2 years ago

What is the strength of the electric field 0.1 mmmm below the center of the bottom surface of the plate

Aleksandr [31]

Complete Question

A thin, horizontal, 12-cm-diameter copper plate is charged to 4.4 nC . Assume that the electrons are uniformly distributed on the surface. What is the strength of the electric field 0.1 mm above the center of the top surface of the plate?

Answer:

The values is $E =248.2 \ N/C$