Answer:
Yes
Explanation:
The given parameters are;
The speed with which the fastball is hit, u = 49.1 m/s (109.9 mph)
The angle in which the fastball is hit, θ = 22°
The distance of the field = 96 m (315 ft)
The range of the projectile motion of the fastball is given by the following formula
![Range = \dfrac{u^2 \times sin(2\cdot \theta)}{g}](https://tex.z-dn.net/?f=Range%20%3D%20%5Cdfrac%7Bu%5E2%20%5Ctimes%20sin%282%5Ccdot%20%5Ctheta%29%7D%7Bg%7D)
Where;
g = The acceleration due to gravity = 9.81 m/s², we have;
![Range = \dfrac{49.1^2 \times sin(2\times22^{\circ})}{9.81} \approx 170.71 \ m](https://tex.z-dn.net/?f=Range%20%3D%20%5Cdfrac%7B49.1%5E2%20%5Ctimes%20sin%282%5Ctimes22%5E%7B%5Ccirc%7D%29%7D%7B9.81%7D%20%5Capprox%20170.71%20%5C%20m)
Yes, given that the ball's range is larger than the extent of the field, the batter is able to safely reach home.
Answer:
Technician A
Explanation:
If Technician B was correct, and the master cylinder is defective - then no braking action would occur.
This is not true however, as some breaking action eventually occurs, meaning it must be out of adjustment.
Answer: Addition polymerization & Condensation polymerization
Answer:
Depending on which hemisphere it is, like western to eastern, It would most likely get stuck at the center. You would also have to put more things into thought like acceleration, velocity, and speed.
BUT since the question asked "would it pop out the other side?", I'm assuming it's talking about northern to southern hemisphere. so in that case it would pop out the other side since gravity makes things go downwards.
The last one, the soil will become weak & unable to support plant growth