3 years ago

At time=0s, the object is at the 21.0-meter position along the roadway. Where is the object at time = 10 s?

1 answer:

4 0

B.) 70m is your answer!

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Sveta_85 [38]

Displacement = 0, assuming that he runs back to original position
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maw [93]

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Answer:

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tino4ka555 [31]

(A). 7.6 kg-m/s is the answer

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Xelga [282]

As we know that it has all given data given as

$v_i = 14 m/s$

$v_f = 25 m/s$

distance moved = 0.250 km = 250 m

now we can use kinematics to find acceleration

$v_f^2 - v_i^2 = 2 a d$

$25^2 - 14^2 = 2 * a * 250$

$a = 0.86 m/s^2$

so it will accelerate at rate of 0.86 m/s^2

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3 years ago