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2 years ago

1.03 Transformation of energy flvs science question

Physics

1 answer:

FinnZ [79.3K]2 years ago

7 0

Explanation:

the process of conversion of energy from one form to another is called transformation of energy.

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which obstacle to problem solving involves arriving at a solution based on your preconceptions and ignoring any evidence that go

White raven [17]

Answer:

confirmation bias

Explanation:

the tendency to interpret new evidence as confirmation of one's existing beliefs or theories in a way that affirms one's prior beliefs or hypotheses.

5 0

3 years ago

What are found on the left side of the arrow in a chemical reaction?

Otrada [13]

The reactants are found on the left side of the "yields" arrow and the product is on the right.

4 0

3 years ago

A particle of mass M moves along a straight line with initial speed vi. A force of magnitude F pushes the particle a distance D

IrinaVladis [17]

Solution :

From the Newton's second law of motion :

F = ma

$a=\frac{F}{m}$

$\frac{dv}{dt}=\frac{F}{m}$

$\left(\frac{dv}{ds} \times \frac{ds}{dt}\right)=\frac{F}{m}$

$v \frac{dv}{ds} = \frac{F}{m}$

$v dv =\frac{F}{m}\ ds$

Integrating above the expression by applying the limits :

$\int_{v_i}^{v_f} v \ dv= \frac{F}{m} \int_0^s ds$

Here the diameter is s= D

$\frac{v_f^2 - v_i^2}{2}=\frac{FD}{m}$

The final speed of the particle after travelling distance D is

$v_f = \sqrt{v_i^2 + \frac{2FD}{m}}$

The kinetic energy of the particle of mass M is :

$K_1=\frac{1}{2}Mv^2$

For M = 3M

$K_2=\frac{1}{2}(3M)v^2$

$=3(K_1)$

Thus the kinetic energy increases by a factor of 3.

The work done depends on the factor and the displacement of the body. Thus, the work done remains same even though the mass increases. Hence the work down increases by factor 1.

8 0

2 years ago

The mass of a 30 cm3 stone is 180 g.

Softa [21]

Your question answer is here
a. Solution ,
Given volume (V)=30cm^3
Mass = 180 g
Density =?
We know that,
Density = given mass/volume
Or. 180/30
=6g/cm^3

b. We know ,
If any pice of stone have equal density so each piece have 6g/cm^3

c. We know ,
Given weight = 80g
Density = 6g/cm^3
Volume =?
We know that,
Volume = given weight ( mass)/ density
= 80/6
= 13.33 cm^3

7 0

2 years ago

If a simple pendulum oscillates with small amplitude and its length is doubled, what happens to the frequency of its motion? It

wel

Answer:

The new frequency will increase by a factor of $\dfrac{1}{\sqrt2}$ .

Explanation:

The frequency of a simple pendulum is given by the formula as follows :

$f=\dfrac{1}{2\pi }\sqrt{\dfrac{g}{l}}$

Here,

l is the length of the simple pendulum

g is acceleration due to gravity on which the pendulum is kept

The frequency of simple pendulum is independent of its amplitude. If a simple pendulum oscillates with small amplitude and its length is doubled, l' = 2l

$f'=\dfrac{1}{2\pi }\sqrt{\dfrac{g}{l'}}\\\\f'=\dfrac{1}{\sqrt2}\times \dfrac{1}{2\pi }\sqrt{\dfrac{g}{l}}\\\\f'=\dfrac{1}{\sqrt2}\times f$

So, the new frequency will increase by a factor of $\dfrac{1}{\sqrt2}$ . Hence, this is the required solution.

4 0

2 years ago

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