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Natasha_Volkova [10]
3 years ago
14

You drive a car from Milwaukee to Chicago, which is a distance of 150km and it takes you 95 min. What is its velocity in km/hr a

nd m/s?
Physics
2 answers:
Softa [21]3 years ago
7 0
94.74 & 26.3 I believe are the answers you are looking for! Hope this helps
Shalnov [3]3 years ago
5 0

Answer:

94.74 km/hr

26.3 meters/sec

Explanation:

150 km/(95/60) hr = 9000/95 kph  = 94.74 km/hr

(150 km * 1000m/km)/(95 min * 60 sec/min) = 150000/5700 m/sec  

= 26.3 meters/sec

Hopefully, this is right!

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You are designing a rotating metal flywheel that will be used to store energy. The flywheel is to be a uniform disk with radius
Gennadij [26K]

Answer:

t = 0.0735 m

Explanation:

Angular acceleration of the flywheel is given as

\alpha = 3 rad/s^2

now after t = 8 s the speed of the flywheel is given as

\omega = \alpha t

\omega = 3 \times 8

\omega = 24 rad/s

now rotational kinetic energy of the wheel is given as

K = \frac{1}{2}I\omega^2

K = \frac{1}{2}(\frac{1}{2}mR^2)(24^2)

800 = \frac{1}{4}m(0.23)^2(24^2)

m = 105 kg

now we have

m = \rho (\pi R^2) t

105 = 8600(\pi \times 0.23^2) t

t = 0.0735 m

4 0
3 years ago
PLEASE HALP ;w;
givi [52]
A haha snake e enajene. skskskksksks and
4 0
3 years ago
The acceleration due to gravity on jupiter is 2.5 times whats on earth. An object of mass 10kg is taken to Jupiter. What is the
Damm [24]
The mass is still 10 kg. But instead of weighing 98N as it does on Earth, it weighs 245N on Jupiter.
4 0
4 years ago
In an Atwood's machine, one block has a mass of 602.0 g, and the other a mass of 717.0 g. The pulley, which is mounted in horizo
Wittaler [7]

Answer:

The acceleration of the both masses is 0.0244 m/s².

Explanation:

Given that,

Mass of one block = 602.0 g

Mass of other block = 717.0 g

Radius = 1.70 cm

Height = 60.6 cm

Time = 7.00 s

Suppose we find  the magnitude of the acceleration of the 602.0-g block

We need to calculate the acceleration

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Where, s = distance

t = time

a = acceleration

Put the value into the formula

60.0\times10^{-2}=0+\dfrac{1}{2}\times a\times(7.00)^2

a=\dfrac{60.0\times10^{-2}\times2}{(7.00)^2}

a=0.0244\ m/s^2

Hence, The acceleration of the both masses is 0.0244 m/s².

5 0
4 years ago
How much thermal energy is needed to melt 1.25 kg of water at its melting point? Use Q = masslaten heat of fusion.
Amanda [17]

Answer:

Latent heatnof fusion = 417.5 J

Explanation:

Specific latent heat of fusion of water is 334kJ.kg-1.

The heat required to melt water when it's ice I called latent heat because there is no temperature change, the only change observed is change in physical structure.

The amount of heat required to change 1 kg of solid to its liquid state (at its melting point) at atmospheric pressure is called Latent heat of Fusion.

Latent heat = ML

Latent heat= 1.25 kg * 334kJ.kg-1

Latent heat = 1.25*334 *(J/kg)*kg

Latent heat = 417.5 J

8 0
3 years ago
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