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inessss [21]
3 years ago
15

PLEASE PLEASE HELPPPPPP!!!!!!!’

Physics
1 answer:
Ostrovityanka [42]3 years ago
3 0
The answer is B

explanation
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an elevator mass of 7700 kg falls from a height of 32 m after a sudden failure in the hoisting cable. The mass is stopped by a s
valkas [14]

Answer:k=28.29 kN/m

Explanation:

Given

mass m =7700 kg

height from which Elevator falls h=32 m

Let x be the compression in the spring

thus From conservation of Energy Potential energy will convert in to Elastic Potential Energy of spring

\frac{kx^2}{2}=mg(h+x)----------1

also maximum acceleration is 5g

thus

mg-kx=ma

here a=-5g

kx=mg-m(-5g)=6mg

x=\frac{6mg}{k}

Substitute x in equation 1

0.5\times k\times (\frac{6mg}{k})^2=mg(h+\frac{6mg}{k})

18\frac{(mg)^2}{k}=mgh+6\frac{(mg)^2}{k}

k=12\cdot \frac{mg}{h}

k=12\times \frac{7700\times 9.8}{32}

k=28.29 kN/m

4 0
3 years ago
Which object has the most kinetic energy? a bus a car a plane a bicycle
loris [4]

Answer:I would guess a plane

Assuming they all Thad the same velocity....

4 0
3 years ago
A group of students decides to set up an experiment in which they will measure the specific heat of a small amount of metal. The
lesya692 [45]
I think the answer is C
7 0
4 years ago
The element that has an average amu of 40 is represented by the symbol Zr on the Periodic Table of Elements. True False Question
Gnom [1K]

Answer:

False

Explanation:

Becuase the average amu of 40 is represented

6 0
3 years ago
With detailed explaniation
belka [17]
  • Ø=37°
  • Initial velocity=u=20m/s
  • g=10m/s²

#A

\\ \rm\Rrightarrow H_{max}=\dfrac{u^2sin^2\theta}{2g}

\\ \rm\Rrightarrow H_{max}=\dfrac{20^2(sin37)^2}{2(10)}

\\ \rm\Rrightarrow H_{max}=\dfrac{400sin^237}{20}

\\ \rm\Rrightarrow H_{max}=20sin^237

\\ \rm\Rrightarrow H_{max}=7.2m

#B

\\ \rm\Rrightarrow R=\dfrac{u^2sin2\theta}{g}

\\ \rm\Rrightarrow R=\dfrac{20^2sin74}{10}

\\ \rm\Rrightarrow R=40sin74

\\ \rm\Rrightarrow R=38.5m

#C

\\ \rm\Rrightarrow T=\dfrac{2usin\theta}{g}

\\ \rm\Rrightarrow T=\dfrac{2(20)sin37}{10}

\\ \rm\Rrightarrow T=4sin37

\\ \rm\Rrightarrow T=2.4s

Now

\\ \rm\Rrightarrow v=u-gt

\\ \rm\Rrightarrow v=20-10(2.4)

\\ \rm\Rrightarrow v=20-24

\\ \rm\Rrightarrow v=-4m/s

4 0
2 years ago
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