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2 years ago

A. What is the wavelength?

2 answers:

7 0

A wavelength in physics is the distance over which the waves shape repeats. Basically the distance between two successive points. It is measure in the direction of the wave. This means the long the wave length, lower the frequency. In the same manner, shorter the wavelength, higher will be the frequency. Hopefully this helps :) have a great day :)

o-na [289]2 years ago

4 0

Answer:

Wavelength is the distance between successive crests of wave, especially points in a sound wave or electromagnetic

wave.

Explanation:

<h3>I hope it helps ❤❤</h3>

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Select the correct answer.

Morgarella [4.7K]

D all of them is the answer. All three can be used to celebrate sporting events

3 0

2 years ago

An electron is moving in the presence of an electric field of 400 N/C. What force does the electron experience?

yanalaym [24]

Answer:

Explanation:

Given

Electric Field strength $E=400\ N/C$

charge of electron $q=1.6\times 10^{-19}\ C$

Force on the charge particle is given by

$F=qE$

$F=1.6\times 10^{-19}\times 400$

$F=640\times 10^{-19}\ N$

but this force will be acting in the direction opposite to the direction of Electric field because electron is negatively charged

8 0

3 years ago

2) Um gás ideal sofre uma determinada transformação, conforme mostra o gráfico abaixo. Considere

Roman55 [17]

Answer:

yes

Explanation:

5 0

3 years ago

A 4-kg toy car with a speed of 5 m/s collides head-on with a stationary 1-kg car. After the collision, the cars are locked toget

mihalych1998 [28]

Kinetic energy lost in collision is 10 J.

<u>Explanation:</u>

Given,

Mass, $m_{1}$ = 4 kg

Speed, $v_{1}$ = 5 m/s

$m_{2}$ = 1 kg

$v_{2}$ = 0

Speed after collision = 4 m/s

Kinetic energy lost, K×E = ?

During collision, momentum is conserved.

Before collision, the kinetic energy is

$\frac{1}{2} m1 (v1)^2 + \frac{1}{2} m2(v2)^2$

By plugging in the values we get,

$KE = \frac{1}{2} * 4 * (5)^2 + \frac{1}{2} * 1 * (0)^2\\\\KE = \frac{1}{2} * 4 * 25 + 0\\\\$

K×E = 50 J

Therefore, kinetic energy before collision is 50 J

Kinetic energy after collision:

$KE = \frac{1}{2} (4 + 1) * (4)^2 + KE(lost)$

$KE = 40J + KE(lost)$

Since,

Initial Kinetic energy = Final kinetic energy

50 J = 40 J + K×E(lost)

K×E(lost) = 50 J - 40 J

K×E(lost) = 10 J

Therefore, kinetic energy lost in collision is 10 J.

4 0

3 years ago

Calculate the work done if a boy lifts a bag of cement 500N to the floor of a lorry 2.5m above the ground

eduard

Answer:

W = 1250 J = 1.25 KJ

Explanation:

The work done by the boy is due to the change in the position of the cement vertically. Hence, the work done in this case will be equal to the potential energy of the cement:

$W = P.E\\W = mgh$

where,

W = Work done = ?

mg = W = weight of cement = 500 N

h = height covered = 2.5 m

Therefore,

$W = (500\ N)(2.5\ m)$

4 0

2 years ago