Answer:
The pressure reduces to 2.588 bars.
Explanation:
According to Bernoulli's theorem for ideal flow we have
![\frac{P}{\gamma _{w}}+\frac{V^{2}}{2g}+z=constant](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7B%5Cgamma%20_%7Bw%7D%7D%2B%5Cfrac%7BV%5E%7B2%7D%7D%7B2g%7D%2Bz%3Dconstant)
Since the losses are neglected thus applying this theorm between upper and lower porion we have
![\frac{P_{u}}{\gamma _{w}}+\frac{V-{u}^{2}}{2g}+z_{u}=\frac{P_{L}}{\gamma _{w}}+\frac{V{L}^{2}}{2g}+z_{L}](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7Bu%7D%7D%7B%5Cgamma%20_%7Bw%7D%7D%2B%5Cfrac%7BV-%7Bu%7D%5E%7B2%7D%7D%7B2g%7D%2Bz_%7Bu%7D%3D%5Cfrac%7BP_%7BL%7D%7D%7B%5Cgamma%20_%7Bw%7D%7D%2B%5Cfrac%7BV%7BL%7D%5E%7B2%7D%7D%7B2g%7D%2Bz_%7BL%7D)
Now by continuity equation we have
![A_{u}v_{u}=A_{L}v_{L}\\\\\therefore v_{L}=\frac{A_{u}}{A_{L}}\times v_{u}\\\\v_{L}=\frac{d^{2}_{u}}{d^{2}_{L}}\times v_{u}\\\\\therefore v_{L}=\frac{2500}{900}\times 3.5\\\\\therefore v_{L}=9.72m/s](https://tex.z-dn.net/?f=A_%7Bu%7Dv_%7Bu%7D%3DA_%7BL%7Dv_%7BL%7D%5C%5C%5C%5C%5Ctherefore%20v_%7BL%7D%3D%5Cfrac%7BA_%7Bu%7D%7D%7BA_%7BL%7D%7D%5Ctimes%20v_%7Bu%7D%5C%5C%5C%5Cv_%7BL%7D%3D%5Cfrac%7Bd%5E%7B2%7D_%7Bu%7D%7D%7Bd%5E%7B2%7D_%7BL%7D%7D%5Ctimes%20v_%7Bu%7D%5C%5C%5C%5C%5Ctherefore%20v_%7BL%7D%3D%5Cfrac%7B2500%7D%7B900%7D%5Ctimes%203.5%5C%5C%5C%5C%5Ctherefore%20v_%7BL%7D%3D9.72m%2Fs)
Applying the values in the Bernoulli's equation we get
![\frac{P_{L}}{\gamma _{w}}=\frac{300000}{\gamma _{w}}+\frac{3.5^{2}}{2g}-\frac{9.72^{2}}{2g}(\because z_{L}=z_{u})\\\\\frac{P_{L}}{\gamma _{w}}=26.38m\\\\\therefore P_{L}=258885.8Pa\\\\\therefore P_{L}=2.588bars](https://tex.z-dn.net/?f=%5Cfrac%7BP_%7BL%7D%7D%7B%5Cgamma%20_%7Bw%7D%7D%3D%5Cfrac%7B300000%7D%7B%5Cgamma%20_%7Bw%7D%7D%2B%5Cfrac%7B3.5%5E%7B2%7D%7D%7B2g%7D-%5Cfrac%7B9.72%5E%7B2%7D%7D%7B2g%7D%28%5Cbecause%20z_%7BL%7D%3Dz_%7Bu%7D%29%5C%5C%5C%5C%5Cfrac%7BP_%7BL%7D%7D%7B%5Cgamma%20_%7Bw%7D%7D%3D26.38m%5C%5C%5C%5C%5Ctherefore%20P_%7BL%7D%3D258885.8Pa%5C%5C%5C%5C%5Ctherefore%20P_%7BL%7D%3D2.588bars)
Answer:
The reaction at support B
Rb= 235440N
The reaction at support C
RC= 29430N
Explanation : check attachment
Answer:A. No one has ever beat Nancy.
Explanation:
The dormain of discourse in a simple language is the set of entities upon which our discussions are based when discussing about something.
The dormain of discourse is also known simply as universe, can also be said to be a set of entities o
upon which certain variables of interest in some formal treatment may range.
The dormain of discourse is generally attributed to Augustus De Morgan, it was also extensively used by George Boole in his Laws of Thought.
THE LOGICAL UNDERSTANDING OF THE THE QUESTION IS THAT NO ONE HAS EVER BEAT NANCY.