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trapecia [35]
3 years ago
10

Consider CO at 500 K and 1000 kPa at an initial state that expands to a final pressure of 200 kPa in an isentropic manner. Repor

t the final temperature in units of K and using three significant digits.
Engineering
1 answer:
REY [17]3 years ago
7 0

Answer:

T_2=315.69k

Explanation:

Initial Temperature T_1=500K

Initial Pressure P_1=1000kPa

Final Pressure P_2=200kPa

Generally the gas equation is mathematically given by

\frac{T_2}{T_1}=\frac{P_2}{P_1}^{\frac{n-1}{n}}

Where

n for CO=1.4

Therefore

\frac{T_2}{500}=\frac{200}{1000}^{\frac{1.4-1}{1.4}}

T_2=315.69k

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There is a proposal in Brooklyn to construct a new mid-rise apartment building on a vacant lot at the intersection of Avenue A a
Soloha48 [4]

Answer:

a. Park should be adjacent to 48th Street, b. Difference in noise level = 707dBa, c. Yes

Explanation:

Data given for Avenue A

Cars = 496, Medium Truck = 52, Heavy Truck = 19, Buses = 10

Data given for 48th Street

Cars = 822, Medium Truck = 22, Heavy Truck = 8, Buses = 3

Consider the PCEs to be Cars = 1, Medium Truck = 13, Heavy Truck = 47, Buses = 18

a. Noise Level = Number of vehicles x PCE

For Avenue A

Noise level = (496 x 1) + (52 x 13) + (19 x 47) + (10 x 18) = 2245dBa

For 48th Street

Noise level = (822 x 1) + (22 x 13  + (8 x 47) + (3 x 18) = 1538dBa

The park should adjacent to 48th street as it is quieter than Avenue A

b. Let the Setback be 50ft. We know that the reduction of noise for 100ft = 5-8 dBa, hence

For Avenue A Noise Reduction due to 50 ft = (8/100) x 50 = 4dBa

Noise at Setback distance = 2245 - 4 = 2241dBa

Considering the same setback the noise at 48th street would be = 1538 - 4 = 1534 dBa

The difference is noise level between the two sides would be = 2241 - 1534 = 707 dBa

c. Yes the developer concerns are valid because there is a clear difference in noise levels of the two sites. This can be seen even after setting the same Setback. Locating the park next to Avenue A will cause serious noise problems.

8 0
4 years ago
In fully developed laminar flow in a circular pipe the velocity at R/2 (mid-way between the wall surface and the centerline) is
Butoxors [25]

Answer:

u_{max} = 17.334\,\frac{m}{s}

Explanation:

Let consider that velocity profile inside the circular pipe is:

u(r) = 2\cdot U_{avg} \cdot \left(1 - \frac{r^{2}}{R^{2}}  \right)

The average speed at r = \frac{1}{2} \cdot R is:

U_{avg} = \frac{13\,\frac{m}{s} }{2\cdot \left(1-\frac{1}{4}  \right)}

U_{avg} = 8.667\,\frac{m}{s}

The velocity at the center of the pipe is:

u_{max} = 2\cdot U_{avg}

u_{max} = 17.334\,\frac{m}{s}

6 0
3 years ago
Read 2 more answers
You are considering purchasing a compact washing machine, and you have the following information: The Energy Guide claims an est
RSB [31]

Answer: $15.34

Explanation: see image below

8 0
3 years ago
Two technicians are discussing torsion bars. Technician A says that many torsion bars are adjustable to allow for ride height ad
sergij07 [2.7K]

Answer: try asking googol or sirl

Explanation:

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2 years ago
Refers to the capability to keep moving forward on a specified grade.
Mademuasel [1]

Answer:

maneuverability

Explanation:

needless to say, I took the quiz

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3 years ago
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