What the difference between a sodium atom (Na) and a sodium ion (Nal+)
2 answers:
Answer:
Explanation:
Remember that protons have a positive charge of +1 and electrons have a negative charge of -1. Atoms have protons and electrons.
A sodium atom has the electron configuration of 2-8-1. It has 11 electrons and its atomic number (number of protons) is also 11. This means it is a <u>neutral</u> atom because the charges of the electrons (-11) and protons (+11) balance each other out.
However, a sodium ion is different. It loses the 1 valence electron, so it only has 10 electrons. It still has the same atomic number of 11.
It is a not a neutral atom because the charges of the electrons (-10) and protons (+11) do not balance out. It has more protons and a net positive charge of +1. It is a <u>cation</u> or a positively charged ion.
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Answer:
Please see the attachments
Explanation:
Please see the attachments below structures of the 3 isomers of C8H18 that contain 3 methyl branches on the main chain, 2 of which are on the same carbon.
Answer:
600 g K₂SO₄
Explanation:
First write down the complete, balanced chemical equation for such question. In this case:
Cr₂(SO₄)₃ + 2K₃PO₄ → 3K₂SO₄ + 2CrPO₄
Next, calculate molar masses of required compounds mentioned in the question. In this case it is for Cr₂(SO₄)₃ and K₂SO₄.
- Molar mass(MM) of Cr₂(SO₄)₃:
= 2*(MM of Cr) + 3*( MM of S) + 3*4*( MM of O)
= 2*(52) + 3*(32) + 12*(16)
= 104 + 96 + 192
= 392 g
- Molar mass(MM) of K₂SO₄:
= 2*(MM of K) + 1*( MM of S) + 4*( MM of O)
= 2*(39) + 32 + 4*(16)
= 78 + 32 + 64
= 174 g
Here comes the concept of Limiting reagent:
The limiting reagent in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent, since the reaction cannot continue without it. The other reactants present with this are usually in excess and called excess reactants. If quantities of both the reactants are given, then one should apply unitary method and find out the limiting reagent out of the two. Then, determine the amount of product formed or percentage yield.
Also, 1 mole( 392 g) of Cr₂(SO₄)₃ gives 3 moles( 174*3 = 522 g) of K₂SO₄.
Using unitary method, if 392g of Cr₂(SO₄)₃ gives 522 g of K₂SO₄ , then 450 g of Cr₂(SO₄)₃ will give how much of K₂SO₄?
Yeild of K₂SO₄ :
That is 599.3 g.
Since we have not considered molecular masses of individual atoms to 6 decimal places, this number can be approximated to 600g.
Therefore, 600g of K₂SO₄ is produced.