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vivado [14]
3 years ago
12

What the difference between a sodium atom (Na) and a sodium ion (Nal+)

Chemistry
2 answers:
vichka [17]3 years ago
7 0

Answer:

So a sodium atom has the electronic configuration 2,8,1 meaning it has 1 electron on its outer shell. It has a neutral charge since the number of electrons is equal to the number of protons.

A sodium ion is one that has lost the electron on its valence shell. The electronic configuration is 2,8 and it has a positive charge because it has more protons than electrons.

STALIN [3.7K]3 years ago
7 0

Answer:

\boxed {\boxed {\sf Number \  of \  electrons \ and \  net \ charge}}

Explanation:

Remember that protons have a positive charge of +1 and electrons have a negative charge of -1. Atoms have protons and electrons.

A sodium atom has the electron configuration of 2-8-1. It has 11 electrons and its atomic number (number of protons) is also 11. This means it is a <u>neutral</u> atom because the charges of the electrons (-11) and protons (+11) balance each other out.

However, a sodium ion is different. It loses the 1 valence electron, so it only has 10 electrons. It still has the same atomic number of 11.

It is a not a neutral atom because the charges of the electrons (-10) and protons (+11) do not balance out. It has more protons and a net positive charge of +1. It is a <u>cation</u> or a positively charged ion.

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Explanation :

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allsm [11]

Answer:

\large \boxed{\text{0.57 g/mL; 3.7 mL; 6.6 g; 0.366 g/mL}}

Explanation:

1. Density from mass and volume

\text{Density} = \dfrac{\text{mass}}{\text{volume}}\\\\\rho = \dfrac{m}{V}\\\\\rho = \dfrac{\text{8.6 g}}{\text{15 mL}} = \text{0.57 g/mL}\\\text{The density is $\large \boxed{\textbf{0.57 g/mL}}$}

2. Volume from density and mass

V = \text{9.7 g}\times\dfrac{\text{1 mL}}{\text{2.6 g}} = \text{3.7 mL}\\\\\text{The volume is $\large \boxed{\textbf{3.7 mL}}$}

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\text{Mass} = \text{4.1 cm}^{3} \times \dfrac{\text{1.6 g}}{\text{1 cm}^{3}} = \textbf{6.6 g}\\\\\text{The mass is $\large \boxed{\textbf{6.6 g}}$}

4. Density by displacement

Volume of water + object = 24.6 mL

Volume of water                =<u> 12.8 mL</u>

Volume of object               = 11.8 mL

\rho = \dfrac{\text{4.3 g}}{\text{11.8 mL}} = \text{0.36 g/mL}\\\text{The density is $\large \boxed{\textbf{0.36 g/mL}}$}

Your drawing showing water displacement using a graduated cylinder should resemble the figure below.

 

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