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vivado [14]
3 years ago
12

What the difference between a sodium atom (Na) and a sodium ion (Nal+)

Chemistry
2 answers:
vichka [17]3 years ago
7 0

Answer:

So a sodium atom has the electronic configuration 2,8,1 meaning it has 1 electron on its outer shell. It has a neutral charge since the number of electrons is equal to the number of protons.

A sodium ion is one that has lost the electron on its valence shell. The electronic configuration is 2,8 and it has a positive charge because it has more protons than electrons.

STALIN [3.7K]3 years ago
7 0

Answer:

\boxed {\boxed {\sf Number \  of \  electrons \ and \  net \ charge}}

Explanation:

Remember that protons have a positive charge of +1 and electrons have a negative charge of -1. Atoms have protons and electrons.

A sodium atom has the electron configuration of 2-8-1. It has 11 electrons and its atomic number (number of protons) is also 11. This means it is a <u>neutral</u> atom because the charges of the electrons (-11) and protons (+11) balance each other out.

However, a sodium ion is different. It loses the 1 valence electron, so it only has 10 electrons. It still has the same atomic number of 11.

It is a not a neutral atom because the charges of the electrons (-10) and protons (+11) do not balance out. It has more protons and a net positive charge of +1. It is a <u>cation</u> or a positively charged ion.

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First, we determine the number of grams present in one ton of copper oxide. This is:
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We convert this into moles by dividing by the molecular mass of copper oxide, which is:
9.09 x 10⁵ / 79.5 = 11,434 moles

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3 years ago
What must happen to uranium before it can be used as a fuel source?
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If 9.5 × 10²⁵ molecules of CO₂ are produced in a combustion reaction, what is the mass in kg of CO₂ that is produced?
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6.9428 kg of CO2

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"A sphere of radius 0.50 m, temperature 27oC, and emissivity 0.85 is located in an environment of temperature 77oC. What is the
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Explanation:

It is known that formula for area of a sphere is as follows.

                     A = 4 \pi r^{2}

                        = 4 \times 3.14 \times (0.50 m)^{2}

                        = 3.14 m^{2}

    T_{a} = (27 + 273.15) K = 300.15 K

          T = (77 + 273.15) K = 350.15 K

Formula to calculate the net charge is as follows.

             Q = esA(T^{4} - T^{4}_{a})

where,    e = emissivity = 0.85

               s = stefan-boltzmann constant = 5.6703 \times 10^{-8} Wm^{-2} K^{-4}

                A = surface area

Hence, putting the given values into the above formula as follows.

                 Q = esA(T^{4} - T^{4}_{a})

                     = 0.85 \times 5.6703 \times 10^{-8} Wm^{-2} K^{-4} \times 3.14 \times ((350.15)^{4} - (300.15)^{4})

                     = 1046.63 W

Therefore, we can conclude that the net flow of energy transferred to the environment in 1 second is 1046.63 W.

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