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3 years ago

What the difference between a sodium atom (Na) and a sodium ion (Nal+)

Chemistry

2 answers:

vichka [17]3 years ago

7 0

Answer:

So a sodium atom has the electronic configuration 2,8,1 meaning it has 1 electron on its outer shell. It has a neutral charge since the number of electrons is equal to the number of protons.

A sodium ion is one that has lost the electron on its valence shell. The electronic configuration is 2,8 and it has a positive charge because it has more protons than electrons.

STALIN [3.7K]3 years ago

7 0

Answer:

$\boxed {\boxed {\sf Number \ of \ electrons \ and \ net \ charge}}$

Explanation:

Remember that protons have a positive charge of +1 and electrons have a negative charge of -1. Atoms have protons and electrons.

A sodium atom has the electron configuration of 2-8-1. It has 11 electrons and its atomic number (number of protons) is also 11. This means it is a <u>neutral</u> atom because the charges of the electrons (-11) and protons (+11) balance each other out.

However, a sodium ion is different. It loses the 1 valence electron, so it only has 10 electrons. It still has the same atomic number of 11.

It is a not a neutral atom because the charges of the electrons (-10) and protons (+11) do not balance out. It has more protons and a net positive charge of +1. It is a <u>cation</u> or a positively charged ion.

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A topaz crystal has an interplanar spacing (d) of 1.36 Å (1 Å =1×10^[−10] m). Calculate the wavelength of the X-ray that should

bija089 [108]

Answer:

7.0*10-11m or 70Å

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From Bragg's equation, w=2dsinx/n

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3 years ago

A 1.25 g gas sample occupies 663 ml at 25∘ c and 1.00 atm. what is the molar mass of the gas?

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Using ideal gas equation,

$P\times V=n\times R\times T$

Here,

P denotes pressure

V denotes volume

n denotes number of moles of gas

R denotes gas constant

T denotes temperature

The values at STP will be:

P=1 atm

T=25 C+273 K =298.15K

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$Number of moles of gas, n= \frac{Given mass of the gas}{Molar mass of the gas}$

$Number of moles of gas, n= \frac{1.25}{Molar mass of the gas}$

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