In this reaction, Copper is the element being oxidized because it is losing electrons. It starts with a neutral charge (0) and ends up with a 6+ charge. Because its charge is increasing, it is being oxidized (losing electrons).
Answer:
The total heat required is 3.4 kJ
Explanation:
Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
There is a direct proportional relationship between heat and temperature. So, the amount of heat a body receives or transmits is determined by:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
In this case you know;
- c= 4
- m= 10 g
- ΔT= Tfinal - Tinitial= 10 C - 0 C= 10 C
Replacing:
Solving:
<em>Q1= 400 J</em>
On the other hand, you must determine the heat required to convert 0 ∘ C of ice to 0 ∘ C of liquid water by:
Q2=m*heat of fusion
Q2=10 g* 300 
<em>Q2= 3,000 J</em>
The total heat required is:
Q= Q1 + Q2= 400 J + 3,000 J
Q= 3,400 J= 3.4 kJ (1 kJ= 1,000 J)
<u><em>The total heat required is 3.4 kJ</em></u>
Neon is an element because it is a pure atom
Answer:
the stoichiometric coefficient for cobalt is 3
Explanation:
the unbalanced reaction would be
Co(NO₃)₂+ Al → Al(NO₃)₃ + Co
One way to solve is to build a system of linear equations for each element (or group as NO₃) , knowing that the number of atoms of each element is conserved.
For smaller reactions a quick way to solve it can be:
- First the Co as product and as reactant needs to have the same stoichiometric coefficient
- Then the Al as product and as reactant needs to have the same stoichiometric coefficient
- After that we look at the nitrates . There are 2 as reactants and 3 as products . Since the common multiple is 6 then multiply the reactant by 3 and the product by 2.
Finally the balanced equation will be
3 Co(NO₃)₂+ 2 Al → 2 Al(NO₃)₃ + 3 Co
then the stoichiometric coefficient for cobalt is 3
Answer:
0,1 mol
Explanation:
We know that the formula of concentration is C= moles of solute/ volume
0,4 M= moles of solute/ 250 mL
Convert mL to L 250 mL =0,25 L
0,4 M x 0,25 L= moles of solute
0,1 moles= moles of solute
