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sveticcg [70]
3 years ago
9

What is the correct name for the chemical formula N408?

Chemistry
2 answers:
Alexandra [31]3 years ago
7 0

Answer:

molar mass (molar weight)

Explanation:

Gennadij [26K]3 years ago
5 0
Molar mass is the answer .
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How many atoms are there in 3 moles of Fe?
slamgirl [31]
N=N/Na
----. N=nxNa=3x6.023x10^23=<span>1.8069e+24</span>
7 0
3 years ago
Is the following true or false every element in the periodic table follows the aufbau principle
gulaghasi [49]

Answer:

True

Explanation:

It is true that every element in the periodic table follows the Aufbau's principle.

The principle states that "the sublevels with lower energies are filled up before those with higher energies".

  • Sublevels do not fill up in numerical order.
  • This is true when writing the electronic configuration of all atoms on the periodic table.
7 0
3 years ago
A chemist makes a solution of Ca(NO3)2 by dissolving 21.3 g Ca(NO3)2 in water to make 100.0 mL of solution. What is the concentr
anastassius [24]

Answer:

[NO₃⁻ ] = 2.596 M

Explanation:

Ca(NO₃)₂ dissolves in water according to the following equation:

Ca(NO₃)₂ ⇒ Ca²⁺ + 2NO₃⁻

The moles of Ca(NO₃)₂ that dissolve is found as followed:

(21.3 g) / (164.10 g/mol) = 0.1298... mol

The number of NO₃⁻ ions are related to the above quantity by the molar ratio:

(0.1298 mol Ca(NO₃)₂) (2NO₃⁻/Ca(NO₃)₂) = 0.2596...mol NO₃⁻

The concentration of the nitrate ions is then calculated:

[NO₃⁻ ] = (0.2596...mol) / (100.0ml) x (1000mL/L) = 2.596 M

6 0
3 years ago
Are ions always smaller than their neutral atoms
Arturiano [62]

Answer:

The negative ion is larger than the original atom. but the same number of positive protons, the size of the ionic radius will increase. When an atom has its electrons attracted to another atom it becomes a positive ion. The positive ion is smaller than the original atom.

3 0
3 years ago
The density of pure gold is 19.3g/cm3. What is the volume of 1.00 g of pure gold?
soldier1979 [14.2K]

Answer: Volume of 1g of pure gold v=0.05181 \mathrm{cm}^{3}

Given;

Density of a pure gold=19.3 g / c m^{3}

Mass of a pure gold =1g

To find:

Volume of 1g of pure gold

Solution:

According to the formula,

Density= Mass/Volume

     \rho=m / v

Where \rho=density of pure gold

           m=mass of pure gold

          v=volume of pure gold

From the above equation volume can be calculated as

v=m / \rho

Substitute the values of mass and density value in the above equation

v=1 / 19.3

v=0.05181 \mathrm{cm}^{3}

Result:

Thus the volume of 1g of pure gold is v=0.05181 \mathrm{cm}^{3}

8 0
3 years ago
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