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Alexus [3.1K]
3 years ago
12

How many liters of 1.5 M HCl solution would react completely with 2.5 moles Ca(OH)2? (2 points)

Chemistry
1 answer:
mylen [45]3 years ago
6 0
Here’s the math for your answer, which is 3.3 L HCl

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Use this equqation for the problem:4Al+3O2 --> 2Al2O3 How many moles of oxygen are needed to completely react with 14.8 mol o
Lesechka [4]

Each mole of butane needs 6.5 moles of oxygen, so 13 moles of oxygen is required for 2 moles of butane in a complete combustion

7 0
3 years ago
In which substance does phosphorus have a +3 oxidation state
andrew-mc [135]
Options are as follow,

A. P₄O₁₀
B. PCl₅
C. Ca₃(PO₄)₂
<span>D. KH</span>₂PO₃

Answer;
            The correct option is Option-D (KH₂PO₃).

Explanation:
                   Oxidation number of Phosphorous is calculated as,

As the normal oxidation number of K is +1, H is +1 and O is -2 so,

                                       KH₂PO₃  =  0

0 shows that the molecule is neutral. Now puttion values of all elemnts except P,
 
                                  (+1) + (+1)₂ + P + (-2)₃  =  0

                                  +1 + 2 + P - 6  =  0

                                  +3 + P - 6  =  0

                                  +3  + P  =  +6

                                  P  =  +6 - 3

                                  P  =  +3
4 0
3 years ago
A 0.100 M solution of K2SO4 would contain the same total ion concentration as which of the following solutions?0.0800 M Na2CO3 0
AysviL [449]

Answer:

  • <em><u>The third chice: 0.0750 M Na₂SO₄</u></em>

Explanation:

Assume 100% ionization:

<em><u>1) 0.100 M solution K₂SO₄</u></em>

  • K₂SO4 (aq) → 2K⁺ (aq) + SO₄²⁻ (aq)

  • Mole ratios: 1 mol K₂SO4 : 2 mol K⁺  + 1 mol SO₄²⁻ (aq) : 3 mol ions. This is 1 : 3

  • At constant volume, the mole ratios are equal to the concentration ratios (M).

  • 1  M K₂SO₄: 3 M ions = 0.100 M K₂SO₄ / x ⇒ x = 0.300 M ions

This means, that you have to find which of the choices is a solution that contains the same 0.300 M ion concentration.

<u>2) 0.0800 M Na₂CO₃</u>

  • Na₂CO₃ (aq) → 2 Na⁺ + CO₃⁻

  • 1 M Na₂CO₃ / 3 M ions = 0.0800M / x ⇒ x = 0.0267 M ions

This is not equal to 0.300 M, so this solution would not contain the same total concentration as a 0.100 M solution of K₂SO₄, and is not the right answer.

<u>3)  0.100 M NaCl </u>

  • NaCl → Na⁺ + Cl⁻

  • 1 M NaCl / 2 M ions = 0.100 M NaCl / x ⇒ x = 0.200 M ions

This is not equal to 0.300 M ion, so not a correct option.

<u>4) 0.0750 M Na₃PO₄</u>

  • Na₃PO₄ → 3Na⁺ + PO₄³⁻

  • 1 M Na₃PO₄ / 4 M ions = 0.0750 M Na₃PO₄ / x ⇒ x = 0.300 M ions

Hence, this ion concentration is equal to the ion concentration of a 0.100 M solution of K₂SO₄, and is the correct choice.

<u>5)  0.0500 M NaOH </u>

  • NaOH → Na⁺ + OH⁻

  • 1 M NaOH / 2 mol ions = 0.0500 M NaOH / x ⇒ x = 0.100 M ions

Not equal to 0.300 M, so wrong choice.

7 0
3 years ago
What kind of Sr3(PO4)2
dangina [55]
Strontium Phosphate is made from that thing
8 0
3 years ago
What is the frequency of radiation whose wavelength is 0.73 nm?
Travka [436]
405 PHz
I might be wrong because that might be for 0.74 nm. We will see with out people answers
8 0
3 years ago
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