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3 years ago

Write the formula of the conjugate base of the Brønsted-Lowry acic, HF

Chemistry

1 answer:

alexdok [17]3 years ago

5 0

Answer:

Furthermore, because hydrofluoric acid, HF, loses a proton, H+1, to generate its conjugate in the reaction that is shown above, this reactant can be classified as a Brønsted-Lowry acid, and, consequently, the fluoride ion, F–1, is the conjugate base of this acid.

Explanation:

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What is the result of crystals boiling the impure product with too much solvent and then cooling on ice?

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Answer: Option (c) is the correct answer.

Explanation:

It is known that when we tend to dilute an impure product with too much of solvent then it will lead to dissolution of the solute. As a result, the chances of formation of crystal reduces.

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3 years ago

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<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

8 P₄ + 3 S₈ → 8 P₄S₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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S₈: 3 moles
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<h3>Limiting reagent</h3>

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

<h3>Limiting reagent in this case</h3>

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 3 moles of S₈ reacts with 8 moles of P₄, 4 moles of S₈ reacts with how many moles of P₄?

$moles of P_{4} =\frac{4 moles of S_{8} x8 moles of P_{4} }{3 moles of S_{8}}$

<u><em>moles of P₄= 10.667 moles</em></u>

But 10.667 moles of P₄ are not available, 4 moles are available. Since you have less amount of moles than you need to react with 4 moles of S₈, P₄ will be the limiting reagent.

Learn more about the reaction stoichiometry:

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2 years ago

Write the formula of the conjugate base of the Brønsted-Lowry acic, HF​

Write the formula of the conjugate base of the Brønsted-Lowry acic, HF