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3 years ago

Write the formula of the conjugate base of the Brønsted-Lowry acic, HF

Chemistry

1 answer:

alexdok [17]3 years ago

5 0

Answer:

Furthermore, because hydrofluoric acid, HF, loses a proton, H+1, to generate its conjugate in the reaction that is shown above, this reactant can be classified as a Brønsted-Lowry acid, and, consequently, the fluoride ion, F–1, is the conjugate base of this acid.

Explanation:

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if 28.5 g of calcium hydroxide is dissolved in enough water to make 185g of solution what is the percent by mass of calcium hydr

DENIUS [597]

The percent by mass of calcium hydroxide in the solution : 15.41%

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Mass of solute (Ca(OH₂-Calcium hydroxide) : 28.5

Mass of solution = 185 g

$\tt \%mass=\dfrac{mass~solute}{mass~solution}\times 100\%\\\\\%mass=\dfrac{28.5~g}{185~g}\times 100\%\\\\\%mass=15.41\%$

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3 years ago

Write the formula of the conjugate base of the Brønsted-Lowry acic, HF​

Write the formula of the conjugate base of the Brønsted-Lowry acic, HF