Is sound a form of energy?

Chemistry

1 answer:

AysviL [449]3 years ago

4 0

Answer:

Explanation:

because for example when you hit something the object will shake and it will shake because of the energy you used to hit it

You might be interested in

How could we stop an asteroid that we know was going to hit Earth?<br><br><br> Pls help ASAP

myrzilka [38]

Answer:

An object with a high mass close to the Earth could be sent out into a collision course with the asteroid, knocking it off course. When the asteroid is still far from the Earth, a means of deflecting the asteroid is to directly alter its momentum by colliding a spacecraft with the asteroid.

Hope it helps!!

5 0

3 years ago

Read 2 more answers

The substance oxidized causes the other substance to be reduced and is called the:.

blsea [12.9K]

Answer:hydrogen Peroxide

Explanation:

4 0

3 years ago

Read 2 more answers

Suppose that, from measurements in a microscope, you determine that a certain layer of graphene covers an area of 1.50μm2. Conve

irga5000 [103]

One $\mu m$ is $10^{-6}m$ , hence one $\mu m^2$ is $10^{-12}m^2$ , thus $1.50\mu m^2$ is $1.50\cdot10^{-12}\mu m^2$

4 0

3 years ago

Read 2 more answers

I need help with this plz help

schepotkina [342]

Answer:

$\rm ^{103}_{\phantom{1}40}Zr$ , zirconium-103.

Explanation:

In a nuclear reaction, both the mass number and atomic number will conserve.

Let $^{A}_{Z}\mathrm{X}$ represent the unknown particle.

The mass number of a particle is the number on the upper-left corner. The atomic number of a particle is the number on its lower-left corner under the mass number. For example, for the particle $^{A}_{Z}\mathrm{X}$ , $A$ is the mass number while $Z$ while $Z$ is the atomic number.

Sum of mass numbers on the left-hand side of the equation:

$\underbrace{239}_{^{239}_{\phantom{2}94}\mathrm{Pu}} + \underbrace{1}_{^{1}_{0}\mathrm{n}} = 240$ .

Note that there are three neutrons on the right-hand side of the equation. Sum of mass numbers on the right-hand side:

$\underbrace{A}_{^{A}_{Z}\mathrm{X}} + \underbrace{134}_{^{134}_{\phantom{2}54}\mathrm{Xe}} + \underbrace{3\times 1}_{3\;^{1}_{0}\mathrm{n}} = A + 137$ .