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vekshin1
3 years ago
14

Just say Hi and I will give you points......... YW and have fun

Physics
2 answers:
Paladinen [302]3 years ago
7 0

Answer:

Thx, Heyy, and you too!!

crimeas [40]3 years ago
3 0
Hey I hope you have a great rest of your day god bless
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Hot water rises and cold water sinks is a model of thermal energy transfer by conduction.

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A current-carrying wire 1.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10 A and there is
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0.2

Explanation:

F= BIL sin©

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2 years ago
If the white car experiences a change in momentum equal to 105,000 kg*m/s and is in contact with the red car for 5 seconds befor
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Answer:

21000 N

Explanation:

From the question given above, the following data were obtained:

Change in momentum = 105000 kg.m/s

Time = 5s

Force =?

Force is related to momentum and time according to the following formula:

Force = Change in momentum / time

With the above formula, we can calculate the force the white car experience during the collision. This can be obtained as illustrated below:

Change in momentum = 105000 kg.m/s

Time = 5s

Force =?

Force = Change in momentum / time

Force = 105000 / 5

Force = 21000 N

Thus, the white car experience a force of 21000 N during the collision.

4 0
2 years ago
A concave mirror with a radius of curvature of 20 cm has a focal length of
xxTIMURxx [149]

Answer:

A concave mirror has a radius of curvature of 20 cm. What is it's focal length? If an object is placed 15 cm in front of it, where would the image be formed? What is it's magnification?

The focal length is of 10 cm, object distance is 30 cm and magnification is -2.

Explanation:

Given:

A concave mirror:

Radius of curvature of the mirror, as C = 20 cm

Object distance in-front of the mirror = 15 cm

a.

Focal length:

Focal length is half of the radius of curvature.

Focal length of the mirror =  \frac{C}{2} = 10 cm

According to the sign convention we will put the mirror on (0,0) point, of the Cartesian coordinate open towards the negative x-axis.

Object and the focal length are also on the negative x-axis where focal length and image distance will be negative numerically.

b.

We have to find the object distance:

Formula to be use:

⇒ \frac{1}{focal\ length}= \frac{1}{image\ distance} + \frac{1}{object\ distance}

⇒ Plugging the values.

⇒ \frac{1}{-10} =\frac{1}{image\ distance}+\frac{1}{-15}

⇒ \frac{1}{-10} -\frac{1}{-15}=\frac{1}{image\ distance}

⇒ \frac{1}{-10} + \frac{1}{15}=\frac{1}{image\ distance}

⇒ \frac{-3+2}{30} =\frac{1}{image\ distance}

⇒ \frac{-1}{30} =\frac{1}{image\ distance}

⇒ -30\ cm=image\ distance

Image will be formed towards negative x-axis 30 cm away from the pole.

c.

Magnification (m) is the negative ratio of mage distance and object distance:

⇒ m=-\frac{image\ distance}{object\ distance}

⇒ m=-\frac{(-30)}{(-15)}

⇒ m=-2

The focal length of the concave mirror, is of 10 cm, object distance is 30 cm and magnification is -2.

5 0
3 years ago
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