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katen-ka-za [31]
3 years ago
13

1. Add 17.35 g, 25.6 g and 8.498 g. chaper 1 physical quantity 11class .physic​

Physics
1 answer:
Korvikt [17]3 years ago
8 0

51.448 g is the required answer!

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Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton
pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx  

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:


F = K * \Delta{x}

2\:N = 4\:N/cm*\Delta{x}

4\:N/cm*\Delta{x} = 2\:N

\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}

simplify by 2

\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}

\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark

Answer:

B.) 1/2 cm

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I Hope this helps, greetings ... Dexteright02! =)

7 0
3 years ago
According to the text, why is the choice not to attend
iogann1982 [59]

Answer:

The answer is B. Without a college education, workers will actually lose money in the long run.

Explanation:

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3 years ago
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What is the value of the angle of refraction of light from a crown glass slab when the angle of incidence is 50°? The slab has a
Artemon [7]

The angle of refraction is 30.3^{\circ}

Explanation:

Refraction is a wave phenomenon that occurs when a light wave passes through the interface between two mediums. When this occurs, the speed and the direction of the light wave change.

We can find the final direction of the refracted light in this problem by applying Snell's law:

n_i sin \theta_i = n_r sin \theta_r

where

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\theta_i, \theta_r are the angle of incidence and refraction, respectively

In this problem, we have:

n_i = 1.00 (the first medium is air, which has a refractive index of 1.00)

n_r = 1.52 (index of refraction of crown glass)

\theta=50^{\circ} is the angle of incidence

Solving for \theta_r, we find the angle of refraction

\theta_r = sin^{-1}(\frac{n_i sin \theta_i}{n_r})=sin^{-1}(\frac{(1.00)(sin 50^{\circ})}{1.52})=30.3^{\circ}

Learn more about refraction and other wave phenomena:

brainly.com/question/3183125

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3 years ago
A player hits a tennis ball in the air with an initial velocity of 32 meters per second at 35 degrees from the vertical how fast
Mamont248 [21]

Answer: 18.35 m/s

Explanation:

At the highest point of trajectory, the vertical component of the velocity would be zero and the tennis ball would have horizontal component of velocity.

It is given that the initial velocity of the ball is 32 m/s and it makes 35° with the vertical. Hence the horizontal component of the velocity,

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Hence, at the highest point in its trajectory, the tennis ball would be moving with the speed  18.35 m/s.

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<span>A) electromagnetic force </span>
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