Answer:
The ratio is 2:1, that is 2mol C / 1mol O2
Explanation:
First check to see if the equation is balanced. It is so now let's find the ratio.
The ratio is the stoichiomeric coefficient of the element or compound.
Carbon : Oxygen
2C : 1 O2 , so 2:1 ..
Answer:
Q = 5671.05 J
Explanation:
Given data:
Mass of metal = 525 g
Initial temperature = 32.0 °C
Fina temperature = 43.0 °C
Heat absorbed by metal = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
specific heat capacity of metal X = 0.982 J/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 43.00°C - 32.00°C
ΔT = 11.00°C
Q = 525 g × 0.982 J/g.°C × 11.00°C
Q = 5671.05 J
2.45 °C
From the Ideal gas law (Combined gas law)
PV/T = P'V'/T' .....eq 1
Where:
P - initial pressure
V - initial volume
T - initial temperature
P' - final pressure
V' - final volume
T' - final temperature.
To proceed we have to make T the subject from eq.1
Which is, T = P'V'T/PV.......eq.2
We have been provided with;
Standard temperature and pressure (STP)
P = 760 mm Hg (SP - Standard Pressure)
T = 273.15 K (ST - Standard Temperature)
V = 62.65 L
P' = 612.0 mm Hg
V' = 78.31 L
T' = ? (what we require)
Therefore, we substitute the values into eq.2
T' =
.
T' = 275.60 K
T = (275.60 - 273.15) ......To °C
T = 2.45 °C
>>>>> Answer
Have a nice studies.
Fe2(SO4)3 + 6KOH -> 3K2SO4 + 2Fe(OH)3
