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harina [27]
3 years ago
12

Which statement is true about Car A?

Physics
1 answer:
alexira [117]3 years ago
6 0

Answer:

Car A has a velocity of 40 km/hr  west.

Explanation:

The velocity of an object is a vector quantity. It has both magnitudes as well as direction.

Arrows are used to show direction.

Car A is moving towards west. Car B is moving towards east-south direction. Car C is moving towards South direction. Car E is moving towards North direction.

So, the correct option is (a) i.e. Car A has a velocity of 40 km/hr  west.

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Describe the difference between contact forces and field forces.
Salsk061 [2.6K]
Contact forces has to be touching for it to be an actual force. A field force does not have to be touching but it does have to be acting on particles at different positions in a space.
8 0
4 years ago
An object is 30 cm in front of a converging lens with a focal length of 10 cm. Use ray tracing to determine the location of the
poizon [28]

Answer:

Inverted

Real

Explanation:

u = Object distance =  30 cm

v = Image distance

f = Focal length = 10 cm

Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{10}-\frac{1}{30}\\\Rightarrow \frac{1}{v}=\frac{1}{15}\\\Rightarrow v=15\ cm

As, the image distance is positive the image is real and forms on the other side of the lens

m=-\frac{v}{u}\\\Rightarrow m=-\frac{-15}{30}\\\Rightarrow m=-0.5

As, the magnification is negative the image is inverted

3 0
3 years ago
Two radio antennas are 120 m apart on a north-south line, and they radiate in phase at a frequency of 3.4 MHz. All radio measure
chubhunter [2.5K]

Answer:

the smallest angle from the antennas is <em>47.3°</em>

Explanation:

We first need to write the expression for the relation between the wavelength (λ) and the frequency (f) of the wave, and then solve for the wavelength.

Therefore, the relation is:

λ = c /f

where

  • c is the speed of light constant
  • λ is the wavelength
  • f is the frequency

Thus,

λ = (3 × 10⁸ m/s) / (3.4 MHz)

  = (3 × 10⁸ m/s) / (3.4 MHz)(10⁶ Hz/1 MHz)

  = 88.235 m

Therefore, the smallest angle measured (from the north of east) from the antennas for the constructive interference of the two-radio wave can be calculated as

θ = sin⁻¹(λ / d)

where

  • d is the distance between the two radio antennas

Thus,

θ = sin⁻¹(88.235 / 120)

<em>θ = 47.3 °</em>

<em></em>

Therefore, the smallest angle from the antennas, measured north of east, at which constructive interference of two radio waves occurs is <em>47.3 °</em>.

5 0
3 years ago
A runner first runs a displacement A of 3.20 km due south, and then a second displacement B that points due east. (a) The magnit
Doss [256]

Answer: 4,438.96m

Explanation:

(kindly find attachment below)

From the attachment below, it can be seen that the resultant displacement and the other 2 displacements form a right angle triangle, with A+B as the hypotenus, 3.2km as the opposite and the displacement B as the adjacent.

By using phythagoras theorem

H² = O² + A²

(5.38)² = (3.20)² + B²

28.944 = 10.24 + B²

B² = 28.944 - 10.24

B² = 18.7044

B = √18.7044

B = 4.439km to meter is 4.439 * 1000 = 4,438. 96m

3 0
3 years ago
Read 2 more answers
Describe at least two ways that electromagnet force and weak nuclear forces are alike and two ways that they are different.
ruslelena [56]

Different: The weak nuclear force is responsible for radioactive decay within an atom of a substance, while the electromagnetic force causes electrostatic force between charged particles.


Different: The weak force has a very small range of effectiveness (where the force can be felt) while the electromagnetic force has an infinite range.


Same: Both forces act within an nucleus, or on a nuclear level.


Same: The weak nuclear force is mediated by charged particles called bosons, and the electrostatic force is only present within charged objects


The last one may be a bit of a stretch but I hope this helped a bit!

4 0
3 years ago
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