All categories

3 years ago

Describe the difference between contact forces and field forces.

1 answer:

8 0

Contact forces has to be touching for it to be an actual force. A field force does not have to be touching but it does have to be acting on particles at different positions in a space.

You might be interested in

Which description accurately describes the tide represented by the image below?

igomit [66]

<span>The gravitational pull of the sun and moon combined
create larger than normal tides.</span>

8 0

3 years ago

Read 2 more answers

A bike travels 4 miles in half an hour at what speed

Sloan [31]

8 miles per hour
because if it is moving at 4 miles every half hour that means you have to multiply it by two to get it in miles per hour and we all know that 4 times 2 is 8 so it would be 8 miles per hour =)

5 0

3 years ago

Read 2 more answers

As the mass of an object increases, the weight of the object will ______?

Sergio039 [100]

Answer:

also increase

Explanation:

If the mass increases so will the weight.

4 0

2 years ago

A man on the moon throws a ball vertically upwards and it is noticed that the ball travels 3.0m less in the fifth second of its

sdas [7]

<h2>Acceleration due to gravity in moon is 1.5 m/s²</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

Here the ball travels 3 m less distance in fifth second compared to third second.

That is

s₃ = s₅ + 3

Now we have

Distance traveled in third second, s₃ = u x 3 - 0.5 x g x 3² - u x 2 - 0.5 x g x 2²

s₃ = u - 2.5 g

Also

Distance traveled in fifth second, s₅ = u x 5 - 0.5 x g x 5² - u x 4 - 0.5 x g x 4²

s₅ = u - 4.5 g

That is

u - 2.5 g = u - 4.5 g + 3

2 g = 3

g = 1.5 m/s²

Acceleration due to gravity in moon = 1.5 m/s²

8 0

2 years ago

Since astronauts in orbit are apparently weightless, a clever method of measuring their masses is needed to monitor their mass g

djyliett [7]

Answer:

a) m = 69.0 kg

b) release some gas in the opposite direction to the astronaut's movement

Explanation:

a) Let's use Newton's second law

F = m a

m = F / a

m = 60.0 / 0.870

m = 69.0 kg

b) when we exert a force on the astronaut it acquires a momentum po, as the astronaut system plus spacecraft is isolated, the momentum is conserved

p₀ = p_f

m v = M v '

v ’= $\frac{m}{M} \ v$

so we see that the ship is moving backwards, but since the mass of the ship is much greater than the mass of the astronaut, the speed of the ship is very small.

One method to avoid this effect is to release some gas in the opposite direction to the astronaut's movement so that the initial momentum of the astronaut plus the gas is zero and therefore no movement is created in the spacecraft.

3 0

2 years ago