Answer:
I =  (K+5)
(K+5)
Explanation:
Given :
J = k+5
Now selecting a thin ring in the wire of radius "r" and thickness dr.
Current through the thin ring is
dI = J X 2πrdr
dI = (K+5) x 2πrdr 
Now integrating we get
I = 
I = (K+5) 2π
I = (K+5) 2π 
I =  (K+5)
(K+5)
 
        
             
        
        
        
It will not be carried to children ... because genetic defect can be carried to children, not the defect during his lifetime
        
             
        
        
        
Answer:
C. The car from driving off the road on a curve
Explanation:
A centripetal force actually causes circular motion. This occurs when an object moves in a circular path or a circle,a force will definitely act on it.
For instance, a car travelling in a circular path must definitely experience this force acting on it, even when the car moves at a constant speed. If it does not exist the object will definitely spin off in a direction tangential to the circular path or curve.
 
        
             
        
        
        
Answer:
Explanation:
Initial velocity u = V₀ in upward direction so it will be negative 
u = - V₀
Displacement s = H . It is downwards so it will be positive 
Acceleration = g ( positive as it is also downwards )
Using the formula 
v² = u² + 2 g s 
v² = (- V₀ )² + 2 g H 
= V₀² + 2 g H . 
v = √ ( V₀² + 2 g H ) 
 
        
             
        
        
        
Answer:
r₁/r₂ = 1/2 = 0.5
Explanation:
The resistance of a wire is given by the following formula:
R = ρL/A
where,
R = Resistance of wire
ρ = resistivity of the material of wire
L = Length of wire
A = Cross-sectional area of wire = πr²
r = radius of wire
Therefore,
R = ρL/πr²
<u>FOR WIRE A</u>:
R₁ = ρ₁L₁/πr₁²   -------- equation 1
<u>FOR WIRE B</u>:
R₂ = ρ₂L₂/πr₂²   -------- equation 2
It is given that resistance of wire A is four times greater than the resistance of wire B. 
R₁ = 4 R₂
using values from equation 1 and equation 2:
ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²
since, the material and length of both wires are same.
ρ₁ = ρ₂ = ρ
L₁ = L₂ = L
Therefore,
ρL/πr₁² = 4ρL/πr₂²
1/r₁² = 4/r₂²
r₁²/r₂² = 1/4
taking square root on both sides:
<u>r₁/r₂ = 1/2 = 0.5</u>