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Sedaia [141]
3 years ago
6

After attending his cousin's birthday party in his backyard, Michael forgot his balloon outside when he went to bed. Overnight,

the temperature dropped significantly. When Michael saw the same balloon the next morning, it looked different. Why did this happen?
Chemistry
1 answer:
Vitek1552 [10]3 years ago
5 0

Answer:

See explanation

Explanation:

You see, we must cast our minds back to Charles' law. Charles' law gives the relationship between the volume of a gas and temperature of the gas.

Now, Micheal left the balloon outside at a particular temperature and volume the previous night. Overnight, the temperature dropped significantly and so must the volume of the gas in the balloon!

Remember that Charles' law states that, the volume of a given mass of gas is directly proportional to its absolute temperature at constant pressure. Since the pressure was held constant, the drop in the volume of gas in the balloon can be accounted for by the drop in temperature overnight.

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At 3 atm pressure the volume of gas is 1200ml. What pressure is required to reduce the volume of the gas to 300ml if the tempera
Rufina [12.5K]
States that when a gas is held at a constant temperature and mass in a closed container, the volume and pressure vary inversely. The equation to use is P1V1=P2V2.

Given
V1=200mL×1L1000mL=0.2 L
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Unknown
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Equation
P1V1=P2V2

Solution
Rearrange the equation to isolate P2 and solve.

P2=P1V1V2

P2=(700mmHg×0.2L)0.1L=1400 L, which must be rounded to 1000 L because all of the measurements have only one significant figure.

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