Answer:
11.6mL of the 0.1400M NaOH solution
Explanation:
<em>0.154g of chloroacetic acid diluted to 250mL. Titrated wit 0.1400M NaOH solution.</em>
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The reaction of chloroacetic acid, ClCH₂COOH (Molar mass: 94.5g/mol) with NaOH is:
ClCH₂COOH + NaOH → ClCH₂COO⁻ + Na⁺ + H₂O
<em>Where 1 mole of the acid reacts per mole of the base.</em>
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That means the student will reach equivalence point when moles of chloroacetic acid = moles NaOH.
You will titrate the 0.154g of ClCH₂COOH. In moles (Using molar mass) are:
0.154g ₓ (1mol / 94.5g) = <em>1.63x10⁻³ moles of ClCH₂COOH</em>
To reach equivalence point, the student must add 1.63x10⁻³ moles of NaOH. These moles comes from:
1.63x10⁻³ moles of NaOH ₓ (1L / 0.1400moles NaOH) = 0.0116L of the 0.1400M NaOH =
<h3>11.6mL of the 0.1400M NaOH solution</h3>
Answer:Use the Law of Sines to solve the triangle ABC if it exists: a) A= 68.41°, B = 54.23”, a = 12.75 ft. b = b = b = a sub ź111347.
Explanation:
Answer:
Cs
Explanation:
This element is the farthest right, and lowest meaning that the reactivity of it is very high.
1. valence electrons and electronegativity
2. Both reactivity and electronegativity decrease down a group.
3. Electronegativity decreases down a group, and reactivity increases down a group.
4. The number of valence electrons increases from left to right.
5. Cs
{quizlet: captncrun}
If we compare a cell with an egg there is a major difference between the outer membrane
in case of cell they are bounded by semi permeable membrane
The semi permeable membrane is a selectively permeable membrane which allows the movement of only solvent molecule and not solute molecules through it.
So water can move into or out of the cell through cell membrane by a special physical process known as osmosis.
the water will move from a low concentration gradient to high concentration gradient.
