Any one help me in 12year physics tell about important long question

Bird bones have air pockets in them to reduce their weight. This also gives them an average density significantly less than that

mixas84 [53]

Answer:

mas of water displaced = 41.4 g

Explanation:

Weight in air = True weight = 45 g

Apparent weight = 3.6 g

Apparent weight = True weight - Buoyant force

Buoyant force = 45 g - 3.6 g = 41.4 g

Weight of water displaced = Buoyant force

Weight of water displaced = 41.4 g dyne

mas of water displaced = 41.4 g

8 0

3 years ago

A clown at a birthday party has brought along a helium cylinder, with which he intends to fill balloons. When full, each balloon

Furkat [3]

Answer:

11

Explanation:

According to Boyle's law:

$P\times V=constant$

Thus,

$P_{cylinder}\times V_{cylinder}=n\times P_{balloon}\times V_{balloon}$

Where, n is the number of the balloons

From the question, it is given that:

For balloon:

P = $1.2\times 10^5$ Pa

V = 0.040 m³

For cylinder:

P = $1.80\times 10^7$ Pa

V = 0.0031 m³

So,

$1.80\times 10^7\times 0.0031=n\times 1.2\times 10^5\times 0.040$

n = 11.625

<u>So, Maximum number of balloons = 11</u>

7 0

3 years ago

- Contemporary World Issues -

kupik [55]

Answer:

hey wsg

Explanation:

8 0

3 years ago

What does the rotational speed of the ring module have to be so that an astronaut standing on the outer rim of the ring module f

Usimov [2.4K]

Complete question:

In the movie The Martian, astronauts travel to Mars in a spaceship called Hermes. This ship has a ring module that rotates around the ship to create “artificial gravity” within the module. Astronauts standing inside the ring module on the outer rim feel like they are standing on the surface of the Earth. (The trailer for this movie shows Hermes at t=2:19 and demonstrates the “artificial gravity” concept between t= 2:19 and t=2:24.)

Analyzing a still frame from the trailer and using the height of the actress to set the scale, you determine that the distance from the center of the ship to the outer rim of the ring module is 11.60 m

What does the rotational speed of the ring module have to be so that an astronaut standing on the outer rim of the ring module feels like they are standing on the surface of the Earth?

Answer:

The rotational speed of the ring module have to be 0.92 rad/s

Explanation:

Given;

the distance from the center of the ship to the outer rim of the ring module r, = 11.60 m

When the astronaut standing on the outer rim of the ring module feels like they are standing on the surface of the Earth, then their centripetal acceleration will be equal to acceleration due to gravity of Earth.

Centripetal acceleration, a = g = 9.8 m/s²

Centripetal acceleration, a = v²/r

But v = ωr

a = g = ω²r

$\omega = \sqrt{\frac{g}{r}} = \sqrt{\frac{9.8}{11.6} } = 0.92 \ rad/s$

Therefore, the rotational speed of the ring module have to be 0.92 rad/s

3 0

3 years ago

The final velocity of car is 20 m/s. The car is accelerating at a rate of 2.5m/s over a 10 seconds period of time. What is the i

balu736 [363]

Answer:

-5m/s

Explanation:

Since

acceleration=final velocity-initial velocity/time

2.5m/s^2=20m/s- initial velocity/10s

2.5m/s^2×10s= 20m/s -initial velocity

25m/s=20m/s - initial velocity

Initial velocity=20m/s-25m/s

= -5m/s

4 0

3 years ago

Any one help me in 12year physics tell about important long question​

Any one help me in 12year physics tell about important long question